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miss Akunina [59]
3 years ago
12

A brass ring of diameter 10.00 cm at 20.0 ^ { \circ } \mathrm { C }20.0 ∘C is heated and slipped over an aluminum rod of diamete

r 10.01 cm at 20.0 ^ { \circ } \mathrm { C }20.0 ∘C. Assuming the average coefficients of linear expansion are constant, What if the aluminum rod were 10.02 cm in diameter?
Physics
1 answer:
VARVARA [1.3K]3 years ago
4 0

Answer:

b)using

DT = (LAl - LBr) / (LBr aBr - LAl aAl)

DT = (10.02-10)/(10*19x10-6 –10.02*24x10-6)

DT = -396 C°

20°C + -396 C° < -273.15 °C;

So the temperature will be -396° this is unattainable because we can’t go below absolute zero

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Answer: well since you can fit one million Earths in the sun just multiply.

hope this helps happy thanksgiving ;)

8 0
3 years ago
Explain
fenix001 [56]

Answer and Explanation:

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7 0
3 years ago
wide tube that extends down from the bag of solution, which hangs from a pole so that the fluid level is 90.0 cm above the needl
Bingel [31]

Answer:

The average gauge pressure inside the vein is 110270.58 Pa

Explanation:

This question can be solved using the Bernoulli's Equation. First, in order to determine the outlet pressure of the needle, we need to find the total pressure exerted by the atmosphere and the fluid.

P_f: fluid's\ pressure\\P_f= \rho g h=1025\frac{kg}{m^3} \times 9.8 \frac{m}{s^2} \times 0.9 m=9040.5 Pa \\P_T: total\ pressure\\P_T=P_{atm}+P_f\\P_T=101325 Pa + 9040.5 Pa=110275.5 Pa\\

Then, we have to find the fluid's outlet velocity with the transversal area of the needle, as follows:

S: transversal\ area \\S= \pi r^2=\pi (0.200 \times 10^{-3})^2=5.65 \times 10^{-7} m^2\\v=\frac{F}{S}=\frac{5.55 \times 10^{-8} \frac{m^3}{s}}{5.65 \times 10^{-7} m^2}=0.98\times 10^{-1} \frac{m}{s}

As we have all the information, we can complete the Bernoulli's expression and solve to find the outlet pressure as follows:

P_T-P_{out}=\frac{1}{2} \rho v^2\\P_{out}=P_T-\frac{1}{2} \rho v^2=110275.5 Pa-\frac{1}{2} 1025\frac{kg}{m^3} (0.98\times 10^{-1} \frac{m}{s})^2=110275.5 Pa-4.92 Pa =110270.58 Pa

6 0
3 years ago
Balanced forces keep this boy in place on his chair. What
I am Lyosha [343]

While the boy is sitting on the chair it creates a force downward on the chair and therefore the chair takes it and gives off the equal amount of force. So while he is putting force downward the chair is putting the same force upward.

3 0
3 years ago
If a woman needs an amplification of 1.0 ✕ 105 times the threshold intensity to enable her to hear at all frequencies, what is h
Damm [24]

Answer:

50 dB.

Explanation:

given,

Amplification needed by the woman,I= 1 x 10⁵ I₀

where as I₀ is the threshold frequency

overall hearing loss of the woman= ?

Using the equation of sound intensity level

\beta(dB) = 10 log(\dfrac{I}{I_0})

\beta(dB) = 10 log(\dfrac{1\times 10^5\ I_0}{I_0})

\beta(dB) = 10 log(1\times 10^5)

\beta(dB) = 50\ dB

The overall hearing loss of woman is equal to 50 dB.

7 0
4 years ago
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