Option A:
The shortest distance Mark can cover to reach home early is 54.7 miles.
Solution:
Towards North = 35 miles
Towards West = 42 miles
Using Pythagoras theorem,
<em>In right triangle, squares of the hypotenuse is equal to the sum of the squares of the other two sides.</em>
Let x be the hypotenuse.



Taking square root on both sides, we get

x = 54.67
x = 54.7
The shortest distance Mark can cover to reach home early is 54.7 miles.
Option A is the correct answer.
Answer:
Step-by-step explanation:
You are given values for x. Plug them in to the given equations. Graph the two lines. Find the intersection. You can tell from the chart when you get the same y value for both equations
tree = 32 2/5 = 162/5
flagpole = (5/9)*(162/5)
Ramiro = (3/10)*(5/9)*(162/5)
= 162/30
= 5.4
or as fraction: 5 2/5
Answer:
Part A)

Part B)

Step-by-step explanation:
We know that the rectangle has a length of (x+5) and a width of 12 cm.
Part A)
Remember the formula for the perimeter of a rectangle:

We know that the perimeter is 86. Substitute that for P:

Substitute (x+5) for the length l and 17 for w. So:

We can simplify this to acquire our equation:

Part B)
To find the length, let's find our x first. We have the equation:

Divide both sides by 2:

Now, subtract 22 from both sides. Therefore, our x is:

To find the length, remember that the length is:

Since we now know the value of x, substitute 21 for x:

Add:

So, the length is 26 centimeters.
And we're done!