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dsp73
3 years ago
6

How to find the area only of a triangle

Mathematics
1 answer:
Cloud [144]3 years ago
7 0
Area= height(base)/2
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Can someone help solve for X
Morgarella [4.7K]

Answer:

x = 2sqrt(5)

Step-by-step explanation:

We can use the Pythagorean theorem to solve

The legs are x and 8/2 =4

and the hypotenuse is 6

a^2 + b^2 = c^2

x^2 +4^2 = 6^2

x^2 +16 = 36

Subtract 16 from each side

x^2 +16-16=36-16

x^2 = 20

Take the square root of each side

sqrt(x^2) = sqrt(20)

x = sqrt(4*5)

x = sqrt(4) sqrt(5)

x = 2sqrt(5)

5 0
3 years ago
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Beth has 4900 feet of fencing available to enclose a rectangular field. one side of the field lies along a river, so only three
Illusion [34]

Perimeter (P) = 2L + x

            4900 = 2L + x   ⇒  4900 - x = 2L  ⇒ \frac{4900 - x}{2} = L

Area (A) = L · x

A  = (\frac{4900 - x}{2}) (x)

    = \frac{4900x - x^2}{2}

4 0
3 years ago
are there any other considerations that should be taken into account when trying to fit a giant tv into your car
FrozenT [24]
The width and height of the tv as well as the length and width of the back of your car
6 0
3 years ago
The area of a rectangular painting is 1/6 square yard. The width is 2/3 yard. What is the length of the painting use the formula
STatiana [176]

The length of the painting is 1/4.

According to the statement

we have to find the length of the rectangular painting with the help of the given information.

So, For this purpose, we know that the

The given information is:

The area of a rectangular painting is 1/6 square yard. The width is 2/3 yard.

And we have to use the formula

Area = Length * Breadth

So, Substitute the values in it then solve

So,

Area = Length * Breadth

1/6= Length * 2/3

1/6 = 2L/3

1 = 12L/3

1 = 4L

L = 1/4.

The value of the length is 1/4.

So, The length of the painting is 1/4.

Learn more about area of a rectangle here

brainly.com/question/2607596

#SPJ9

4 0
1 year ago
Find x - 3y if x = 3 and y = 2
valentina_108 [34]
I think -3 because 3(2) = 6 (3-6= -3)
3 0
3 years ago
Read 2 more answers
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