Write the formulas of the three singly chlorinated isomers formed when 2,2-dimethylbutane reacts with Cl2 in the presence of lig
ht.
1 answer:
The molecule with same molecular formula but different arrangement of atoms is said to be an isomer.
When 2,2-dimethylbutane reacts with chlorine in the presence of light gives three isomers that is (3-chloro-2,2-dimethylbutane),
(1-chloro-2,2-dimethylbutane) and
(1-chloro-3,3-dimethylbutane).
In above case, the molecular formula of all isomers are same i.e. but chlorine is arranged in different positions of carbon. Thus, results isomers.
The reaction is shown in the image.
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Answer: -
If a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.
Explanation: -
Density of the gasoline = 0.77 kg / liter
Volume of the tank containing the gasoline = 80 liter.
Mass of gasoline produced from each tank
= Volume of the tank containing the gasoline x Density of the gasoline
= x 80 liter
= 61.6 kg
Chemical formula of gasoline = C₈H₁₈
Molar mass of gasoline C₈H₁₈ = 12 x 8 + 1 x 18 = 114 g/ mol
Number of moles of C₈H₁₈ = x 1 mol
= 0.54 mol of C₈H₁₈
The chemical equation for the burning of gasoline is
2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O
From the balanced equation we see
2 mol of C₈H₁₈ gives 16 mol of CO₂
0.54 mol of C₈H₁₈ gives mol of CO₂
= 4.32 mol of CO₂
Molar mass of CO₂ = 12 x 1 + 16 x 3 =60 g / mol
Mass of CO₂ = Molar mass of CO₂ x Number of moles of CO₂
=
= 259.2 g
=
= 0.259 Kg
= 0.26 kg rounded off to 2 significant figures.
Thus if a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.