If a nucleus were as big as a nonpareil, what would a strand of hair be the size of

A sample of nitrogen gas occupies a volume of 2.55 L when it is at 755 mm Hg and 23 degrees Celsius. Use this information to det

ivolga24 [154]

Answer: The number of moles of nitrogen gas are 0.1043 moles and the pressure when volume and temperature has changed is 461.6 mmHg

Explanation:

To calculate the amount of nitrogen gas, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 755 mmHg

V = Volume of the gas = 2.55 L

T = Temperature of the gas = $23^oC=[23+273]K=296K$

R = Gas constant = $62.364\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles of nitrogen gas = ?

Putting values in above equation, we get:

$755mmHg\times 2.55L=n\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 296K\\\\n=\frac{755\times 2.55}{62.364\times 296}=0.1043mol$

To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

$P_1=755mmHg\\V_1=2.55mL\\T_1=23^oC=[23+273]K=296K\\P_2=?\\V_2=4.10L\\T_2=18^oC=[18+273]K=291K$

Putting values in above equation, we get:

$\frac{755mmHg\times 2.55L}{296K}=\frac{P_2\times 4.10L}{291K}\\\\P_2=\frac{755\times 2.55\times 291}{4.10\times 296}=461.6mmHg$

Hence, the number of moles of nitrogen gas are 0.1043 moles and the pressure when volume and temperature has changed is 461.6 mmHg

6 0

3 years ago

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The _______ of a wave is a measure of the amount of energy it carries

Bumek [7]

The word that best fits is frequency. The sentence is The frequency of a wave is a measure of the amount of energy it carries. There is a direct relationship between frequency and energy of a wave. The constant of proportionality is h, Planck's constant. So, Energy = h * frequency. So, the answer is frequency. Although you should know that wavelength is related to frequency and so it is also a measure of the amount of energy and it should also be other valid answer.

6 0

3 years ago

NEED HELP ASAP FREE BRAINLIST

FrozenT [24]

Answer:

7) C. Sodium

8) G. 1 valence electron

Explanation:

8 0

2 years ago

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What is the density of a substance with a mass of 0.0450 and a volume of 26.4?

Tanya [424]

Answer:

$density \: = \frac{mass}{volume} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{0.0450}{26.4} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0.0017 \\$

Explanation:

plz....

Mark it as a brilliant answer

7 0

3 years ago

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How many grams of H2S is needed to produce 18.00g of PbS if the H2S is reacted with an

goldenfox [79]

Answer:

2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an excess (unlimited) supply of Pb(CH₃COO)₂

Explanation:

The balanced reaction is:

Pb(CH₃COO)₂ + H₂S → 2 CH₃COOH + PbS

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) they react and produce:

Pb(CH₃COO)₂: 1 mole
H₂S: 1 mole
CH₃COOH: 2 moles
PbS: 1 mole

In this case, to know how many grams of H₂S are needed to produce 18.00 g of PbS, it is first necessary to know the molar mass of the compounds H₂S and PbS and then to know how much it reacts by stoichiometry. Being:

H: 1 g/mole
S: 32 g/mole
Pb: 207 g/mole

The molar mass of the compounds are:

H₂S: 2* 1 g/mole + 32 g/mole= 34 g/mole
PbS: 207 g/mole + 32 g/mole= 239 g/mole

So, by stoichiometry they react and are produced:

H₂S: 1 mole* 34 g/mole= 34 g
PbS: 1 mole* 239 g/mole= 239 g

Then the following rule of three can be applied: if 239 grams of PbS are produced by stoichiometry from 34 grams of H₂S, 18 grams of PbS from how much mass of H₂S is produced?

$mass of H_{2} S=\frac{18 grams of PbS*34 grams of H_{2}S }{239 grams of PbS}$

mass of H₂S= 2.56 grams

2.56 grams of H₂S is needed to produce 18.00g of PbS if the H2S is reacted with an excess (unlimited) supply of Pb(CH₃COO)₂

8 0

3 years ago