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horsena [70]
3 years ago
13

What is the change in each term of the sequence? 0.8, 1, 1.2, 1.4, 1.6​

Mathematics
2 answers:
Aloiza [94]3 years ago
8 0

Begin by studying the pattern.

Notice that the difference between 0.8 and 1 is 0.2.

In other words, 0.8 + 0.2 is 1.

In the same way, 1 + 0.2 is 1.2.

1.2 + 0.2 is 1.4 and 1.4 + 0.2 is 1.6.

So we can see that the difference

between each of the terms is 0.2.

Roman55 [17]3 years ago
6 0

Answer:

+.2

Step-by-step explanation:

To find the common difference, take the second term and subtract the first term

1 - .8 = .2

Check by subtracting the second term from the third term

1.2 - 1 = .2

The common difference is .2

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Hunter-Best [27]

Answer:

D. -3.3

Step-by-step explanation:

=> 2.8x = -9.24

=> x = -9.24/2.8

=> x = -3.3

5 0
3 years ago
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Anvisha [2.4K]

A die has 6 sides, so rolling a 1 out of all six would be 1/6 which equals a 0.16% chance and same goes for a 2/6.

(Mark as brainliest if I helped in anyway, pls and thanks:))

4 0
3 years ago
Consider the system of differential equations dx/dt=−2y dy/dt=−2x. . Convert this system to a second order differential equation
Musya8 [376]

Answer:

Step-by-step explanation:

we have the following differential equations

\frac{dx}{dt}=-2y\\\frac{dy}{dt}=-2x\\

by differentiating the second equation we have

\frac{d}{dt}(\frac{dy}{dt})=-2\frac{dx}{dt}\\\frac{d^{2}y}{dt^{2}}=-2\frac{dx}{dt}\\\frac{dx}{dt}=\frac{-1}{2}\frac{d^{2}y}{dt^{2}}

and we replace dx/dt in the first equation

\frac{-1}{2}\frac{d^{2}y}{dt^{2}}=-2y\\\frac{d^{2}y}{dt^{2}}-4y=0

and by using the characteristic polynomial

m^{2}+4=0\\m=\±2i

the solution is

y(t)=Acos(2t)+Bsin(2t)

and to compute x(t) we have

\frac{dx}{dt}=-2Acos(2t)-2Bsin(2t)\\\\\int dx = \int[-2Acos(2t)-2Bsin(2t)]dt\\\\x(t)=-Asin(2t)+Bcos(2t)

and if we use x(0)=4 and y(0)=3, we can calculate the constants A and B

x(0)=B=4\\y(0)=A=3

I hope this is useful for you

regards

4 0
3 years ago
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we have

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685*10^{-9} =6.85*10^{-7}

therefore

<u>the answer is</u>

6.85*10^{-7}

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