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Montano1993 [528]
3 years ago
14

"the osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant

r . suppose the osmotic pressure of a certain solution is measured to be 23.atm at an absolute temperature of 309.k"
Chemistry
2 answers:
ASHA 777 [7]3 years ago
8 0

Answer: -

The concentration is 0.91 mol/ L

Explanation: -

The osmotic pressure = 23 atm

Absolute temperature = 309 K

Universal gas constant = 0.08206 L atm mol⁻¹ K⁻¹

We know the formula

Osmotic pressure = molar concentration x universal gas constant x absolute temperature

Plugging in the values

23 atm = molar concentration x 0.08206 L atm mol⁻¹ K⁻¹ x 309 K

Molar concentration = \frac{23}{0.08206 x 309} mol/ L

                                  = 0.91 mol / L

Liula [17]3 years ago
5 0

The concentration is 0.91 mol/ L

Further Explanation:

Solution:

The osmotic pressure = 23 atm  

Absolute temperature = 309 K

Universal gas constant = 0.08206 L atm mol⁻¹ K⁻¹

Formula is:

Osmotic pressure = molar concentration x universal gas constant x absolute temperature

23 atm = molar concentration x 0.08206 L atm mol⁻¹ K⁻¹ x 309 K

Molar concentration= 0.91 mol / L

Osmotic pressure:

Osmotic weight is the base weight which should be connected to an answer for avert the internal progression of its unadulterated dissolvable over a semipermeable layer. It is additionally characterized as the proportion of the propensity of an answer for take in unadulterated dissolvable as a natural side effect.  

A case of osmotic weight:  

An incredible case of a semipermeable layer is that inside the shell of an egg. After shell evacuation is cultivated with acidic corrosive, the film around the egg can be utilized to show assimilation. Karo syrup is basically unadulterated sugar, with almost no water in it, so its osmotic weight is low.  

osmotic weight in basic terms:  

Osmotic weight is the power brought about by an answer going through a semi porous surface without really trying, which is equivalent to the power required to oppose the arrangement from going back through the surface. A case of osmotic weight is the procedure to channel water.

Subject: chemistry

Level: college

Keywords: Solution, Osmotic pressure, A case of osmotic weight, osmotic weight in basic terms.

Related links:

Learn more about evolution on

brainly.com/question/4213901

brainly.com/question/6125309

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The equilibrium constant for the gas phase reaction
stellarik [79]
The equilibrium constant is found by [product]/[reactant]

If the equilibrium constant is very small, such as 4.20 * 10^-31, then that means at equilibrium there is very little product and a lot of reactant.
And likewise, if there is a lot of product formed, and very little reactant, then the K value will be very large, which tells us that it is predominantly product.

At equilibrium, for any reaction, there will always be some reactant and some product present. There cannot be zero reactant or zero product. Also keep in mind that the equilibrium constant is dependent on temperature.

At equilibrium, for your reaction, it is predominantly reactants.
6 0
3 years ago
A sample of a pure compound that weighs 59.8 g contains 27.6 g Sb (antimony) and 32.2 g F (fluorine). What is the percent compos
Rama09 [41]

Answer:

53.85%

Explanation:

Data obtained from the question include:

Mass of antimony (Sb) = 27.6g

Mass of Fluorine (F) = 32.2g

Mass of compound = 59.8g

Percentage composition of fluorine (F) =..?

The percentage composition of fluorine can be obtained as follow:

Percentage composition of fluorine = mass of fluorine/mass of compound x 100

Percentage composition of fluorine = 32.2/59.8 x 100

= 53.85%

Therefore, the percentage composition of fluorine in the compound is 53.85%

3 0
3 years ago
What are the basic building blocks of proteins?
Anna11 [10]

Answer:

Amino Acids

Explanation:

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8 0
3 years ago
The specific heat capacity of concrete is 0.880 J/g °C
nata0808 [166]

Answer:

Solution given:

heat[Q]=?

temperature [T]=0.64°C

specific heat capacity [c]=0.880 J/g °C

mass[m]=3g

we have

Q=mcT=3*0.880*0.64°=1.69Joule

<u>the</u><u> </u><u>required</u><u> heat </u><u>is</u><u> </u><u>1.69</u><u>Joule</u><u>.</u>

5 0
3 years ago
Read 2 more answers
Be sure to answer all parts. How many moles of O are needed to combine with 0.276 mole of C to form CO
Vikki [24]

Answer:

0.138 moles of oxygen are needed to combine with 0.276 moles of carbon.

Explanation:

Given data:

Moles of oxygen needed = ?

Moles of carbon present = 0.276 mol

Solution:

Chemical equation:

2C  + O₂      →        2CO

Now we will compare the moles of carbon with oxygen.

              C            :          O₂  

              2            :            1

             0.276     :        1/2×0.276  = 0.138 mol

Thus, 0.138 moles of oxygen are needed to combine with 0.276 moles of carbon.

7 0
3 years ago
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