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bekas [8.4K]
3 years ago
10

2 h v=/ 3 m=500g d = ?

Chemistry
1 answer:
Snowcat [4.5K]3 years ago
3 0
More details? Can’t do anything wit that
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3,010,000 into scientific notation
skelet666 [1.2K]

Answer:

3.01 x 10 to the power of 6

Explanation:

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 3,010,000

New Number: 3.010000

Step 2

Now, to find b, count how many places to the right of the decimal.

3 0
3 years ago
Read 2 more answers
What the correct answer?
alexandr402 [8]

B. Bleach and sea water should be identified as bases

Explanation:

  • The pH scale measures the acidic or basic nature of a substance.
  • Ranges from 0 to 14.
  • If pH is lower than 7 → the solution is an acid.
  • If pH is more than 7 → the solution is an basic or alkaline.
  • If a pH is a 7 it is neutral.

In the given question, the pH scale measures for bleach is 8 and for sea water it is 13. So, bleach is basic, not neutral and Sea water is basic too instead of acid. So, Bleach and sea water should be identified as bases.

3 0
3 years ago
What elements do not fit the pattern of electron affinity
Pavel [41]
What are the choices?
8 0
3 years ago
2. When vinegar is added to eggshells, carbon dioxide gas is produced.​Why?
skad [1K]

Answer:

same as his

Explanation:

4 0
3 years ago
Calculate the maximum volume in ml of 0.15M HCl that each of the following antacid formulations would be expected to neutralize.
vlada-n [284]

a. 34 mL; b. 110 mL

a. A tablet containing 150 Mg(OH)₂


Mg(OH)₂ + 2HCl ⟶ MgCl₂ + 2H₂O


<em>Moles of Mg(OH)₂</em> = 150 mg Mg(OH)₂ × [1 mmol Mg(OH)₂/58.32 mg Mg(OH)₂

= 2.572 mmol Mg(OH)₂


<em>Moles of HCl</em> = 2.572 mmol Mg(OH)₂ × [2 mmol HCl/1 mmol Mg(OH)₂]

= 5.144 mmol HCl


Volume of HCl = 5.144 mmol HCl × (1 mmol HCl/0.15 mmol HCl) = 34 mL HCl


b. A tablet containing 850 mg CaCO₃


CaCO₃ + 2HCl ⟶ CaCl₂ + CO₂ + H₂O


<em>Moles of CaCO₃</em> = 850 mg CaCO₃ × [1 mmol CaCO₃/100.09 mg CaCO₃

= 8.492 mmol CaCO₃


<em>Moles of HCl</em> = 8.492 mmol CaCO₃ × [2 mmol HCl/1 mmol CaCO₃]

= 16.98 mmol HCl


Volume of HCl = 16.98 mmol HCl × (1 mL HCl/0.15 mmol HCl) = 110 mL HCl


5 0
3 years ago
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