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bekas [8.4K]
3 years ago
10

2 h v=/ 3 m=500g d = ?

Chemistry
1 answer:
Snowcat [4.5K]3 years ago
3 0
More details? Can’t do anything wit that
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Identify the number of each type of atom in this formula 5C12H22O11<br><br>wdym
Lady bird [3.3K]
There are 12 carbon atoms, 22 hydrogen atoms, and 11 oxygen atoms in one molecule of C12H22O11. 
In five molecules there are 60 carbon atoms, 110 hydrogen atoms, and 55 oxygen atoms.
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Question 1 (1 point)<br> ROOTS--What is NOT a root function in plants?
Jlenok [28]

Answer:

deez nuets

Explanation:

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3 0
3 years ago
Need it in 2 minutes ASAP
RUDIKE [14]

Answer: read your book

Explanation: if you read it should be in there

3 0
3 years ago
Based on the equation, how many grams of Br2 are required to react completely with 36.2 grams of AlCl3?
s2008m [1.1K]

Answer:

65.08 g.

Explanation:

  • For the reaction, the balanced equation is:

<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>

2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.

  • Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:

<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>

<u><em>Using cross multiplication:</em></u>

2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.

0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.

∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃  = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.

<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol ) = <em>65.08 g.</em>

4 0
3 years ago
How many carbon atoms are there in .500 mol of CO2?
AURORKA [14]

Answer: There are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

Explanation:

According to the mole concept, there are 6.022 \times 10^{23} atoms present in 1 mole of a substance.

In a molecule of CO_{2} there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of CO_{2} are as follows.

1 \times 0.500 \times 6.022 \times 10^{23}\\= 3.011 \times 10^{23}

Thus, we can conclude that there are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

6 0
3 years ago
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