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bekas [8.4K]
3 years ago
10

2 h v=/ 3 m=500g d = ?

Chemistry
1 answer:
Snowcat [4.5K]3 years ago
3 0
More details? Can’t do anything wit that
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A meteor falls toward Earth's surface. Given that the acceleration due to
ICE Princess25 [194]

Answer:

E = 147000  J

Explanation:

Given that,

The mass of meteor, m = 50 kg

The altitude of the meteor, h = 300 m

We need to find the potential energy of the meteor. The formula for the potential energy is given by :

E=mgh

Put all the values,

E=50\times 9.8\times 300\\\\E=147000\ J

So, the required potential energy is equal to 147000  J.

4 0
3 years ago
In the image above, the girl is using her arm to lift a weight. Her arm is acting as a _______.
Vinvika [58]
B the girls arm will act as a pulley
6 0
3 years ago
After looking at the schematics of the bubble, he finds that it holds 0.750 moles of gas at Standard Temperature and Pressure. U
Lina20 [59]

Answer:

16.8 L

Explanation:

From the question given above, the following data were obtained:

Number of mole of He = 0.750 mole

Volume of He =?

Recall:

1 mole of any gas occupy 22.4 L at STP. This also implies that 1 mole of He occupies 22.4 L at STP.

Finally, we shall determine the volume occupied by 0.750 mole of He. This can be obtained as follow:

1 mole of He occupied 22.4 L at STP.

Therefore, 0.750 mole of He will occupy = 0.750 × 22.4 = 16.8 L at STP.

Thus, 0.750 mole of He is equivalent to 16.8 L

6 0
2 years ago
What is the mass of iron shot, with a dean sigh of 7.92 g/mL. The shot is added to a graduated cylinder containing 25.80 mL of w
VikaD [51]

Answer:

The answer is

<h2>184.54 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

density of iron = 7.92 g/mL

volume = final volume of water - initial volume of water

volume = 49.10 - 25.80

Volume = 23.3 mL

It's mass is

mass = 7.92 × 23.3 = 184.536

We have the final answer as

<h3>184.54 g</h3>

Hope this helps you

7 0
3 years ago
Determine the empirical formula for a compound that is 70.79% carbon, 8.91% hydrogen, 4.59% nitrogen, and 15.72% oxygen. determi
IceJOKER [234]
Hello!

We use the amount in grams (mass ratio) based on the composition of the elements, see: (in 100g solution)

C: 70.79% = 70,79 g 
H: 8.91% = 8.91 g
N: 4.59% = 4.59 g
O: 15.72% = 15.72 g

Let us use the above mentioned data (in g) and values will be ​​converted to amount of substance (number of moles) by dividing by molecular mass (g / mol) each of the values, lets see:

C: \dfrac{70.79\:\diagup\!\!\!\!\!g}{12\:\diagup\!\!\!\!\!g/mol} \approx 5.89\:mol

H: \dfrac{8.91\:\diagup\!\!\!\!\!g}{1\:\diagup\!\!\!\!\!g/mol} = 8.91\:mol

N: \dfrac{4.59\:\diagup\!\!\!\!\!g}{14\:\diagup\!\!\!\!\!g/mol} \approx 0.328\:mol

O: \dfrac{15.72\:\diagup\!\!\!\!\!g}{16\:\diagup\!\!\!\!\!g/mol} = 0.9825\:mol

We note that the values ​​found above are not integers, so let's divide these values ​​by the smallest of them, so that the proportion is not changed, let's see:

C: \dfrac{5.89}{0.328}\to\:\:\boxed{C\approx 18}

H: \dfrac{8.91}{0.328}\to\:\:\boxed{H\approx 27}

N: \dfrac{0.328}{0.328}\to\:\:\boxed{N\approx 1}

O: \dfrac{0.9825}{0.328}\to\:\:\boxed{O\approx 3}

T<span>hus, the minimum or empirical formula found for the compound will be:

</span>\boxed{\boxed{C_{18}H_{27}N_1O_3\:\:or\:\:C_{18}H_{27}NO_3}}\end{array}}\qquad\checkmark

I hope this helps. =)
5 0
3 years ago
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