All categories

3 years ago

Please help I will give brainliest

Mathematics

2 answers:

Musya8 [376]3 years ago

4 0

Answer:

What do u have to do. I don’t see a point on the graph

Step-by-step explanation:

zaharov [31]3 years ago

3 0

Answer:

might have to draw a line through it but here are the points

Step-by-step explanation:

You might be interested in

Can someone please help me with math.

sattari [20]

Answer:

A: strongly positive

Step-by-step explanation:

Hopefully this helps!

6 0

3 years ago

Petra eats five and three fifths pies in a pie-eating contest. Paulie eats three and fourteen sixteenths pies in the contest. Ho

Alex777 [14]

Answer:

2 7/20

Step-by-step explanation:

So Lets put these into a fraction form

Petra: 5 3/5

Pauline: 3 4/16 -> Can be Simplified = 3 1/4

Take the number of pies Petra Ate and subtract it by the number of pies Pauline ate

Change the numbers to a common factor. (multiply 3/5 by 4 and 1/4 by 5 to have common denominators)

$5 \frac{12}{20} - 3 \frac{5}{20}$

Make These Into a Mixed Fraction

$\frac{112}{20} -\frac{65}{20}$

Subtract 112-65

$\frac{47}{20}$

Simplify (divide 47 into 20 how many times to get into a mixed fraction)

$2 \frac{7}{20}$

I think this is right. Hope This Helps

7 0

2 years ago

Read 2 more answers

Tom exercised 4/5 hour on monday and 5/6 hour on tuesday. Complete the calculations below to write equivalent fractions with a c

stepladder [879]

4/5= 24/30 5/6= 25/30 Equals in all= 1 19/30

7 0

3 years ago

If m= 15 and n = 3, what is the value of the following expression?

GaryK [48]

Answer:

Step-by-step explanation:

5 0

3 years ago

Solve the equation <img src="https://tex.z-dn.net/?f=%2835%20x%5E%7B4%7D%20y%2B14%20x%5E%7B5%7D%20y-2%20y%5E%7B3%7D-4x%20y%5E%7B

jeka94

$\underbrace{35x^4y+14x^5y-2y^3-4xy^3}_M\,\mathrm dx+\underbrace{7x^5-6xy^2}_N\,\mathrm dy=0$

$M_y=35x^4+14x^5-6y^2-12xy^2$
$N_x=35x^4-6y^2$

$\dfrac{N_x-M_y}N=\dfrac{-14x^5+12xy^2}{7x^5-6xy^2}=-2$

This suggests an integrating factor depending on $x$ only is possible, and given by

$\mu(x)=\exp\left(-\displaystyle\int\frac{N_x-M_y}N\,\mathrm dx\right)=e^{2x}$

Distributing across the ODE, we end up with

$\underbrace{(35x^4y+14x^5y-2y^3-4xy^3)e^{2x}}_{M^*}\,\mathrm dx+\underbrace{(7x^5-6xy^2)e^{2x}}_{N^*}\,\mathrm dy=0$

The equation is now exact, with

${M^*}_y={N^*}_x=(35x^4+14x^5-6y^2-12xy^2)e^{2x}$

Now we find the solution:

$F_x=M^*$
$F=\displaystyle\int(35x^4+14x^5-2y^3-4xy^3)e^{2x}\,\mathrm dx$
$F=(7x^5y-2xy^3)e^{2x}+f(y)$

$F_y=N^*$
$(7x^5-6xy^2)e^{2x}+f'(y)=(7x^5-6xy^2)e^{2x}$
$f'(y)=0$
$\implies f(y)=C$

The general solution is then

$F(x,y)=(7x^5y-2xy^3)e^{2x}=C$

7 0

3 years ago