Answer: 1.72cm
Explanation:
First let us calculate the mass of titanium that contain 2.86×10^23 atoms..
1mole of a substance contains 6.02x10^23 atoms as we have come to understand from Avogadro's hypothesis. Therefore, 1mole of titanium also contains 6.02x10^23 atoms.
1mole of titanium = 48g
1mole (i.e 48g) of titanium contains 6.02x10^23 atoms,
Therefore Xg of titanium will contain 2.86×10^23 atoms i.e
Xg of titanium = (48x2.86×10^23)/6.02x10^23 = 22.8g
Next, we must find the volume of titanium
Density of titanium = 4.5g/cm^3
Mass of titanium = 22.8g
Volume =?
Density = Mass /volume
Volume = Mass /Density
Volume = 22.8/4.5
Volume = 5.07cm^3
Now we can find the edge length:
Volume = 5.07cm^3
Length =?
V = L^3
L = cube root (V)
L = cube root (5.07)
L = 1.72cm
Answer:
luster
i just did it and its luster
Assuming that the O2 gas acts like an ideal gas, we find
the following expression to be approximates of the behaviour of this gas:
<span>P V = n R T --->
1</span>
where,
P = pressure exerted by the gas
V = volume occupied
n = number of moles
R = universal gas constant
T = absolute temperature
Further, we assume that the number of moles and the
temperature are constant, hence reducing equation 1 into the form:
<span>P V = k --->
2</span>
where k is a constant. Therefore we can equate two
states:
P1 V1 = P2 V2
Since P1, V1 and V2 are given and we are to look for P2:
25 mL * 2 atm = 100 mL * P2
<span>P2 = 0.5 atm</span>
