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Ann [662]
3 years ago
9

Someone please help me with this????

Chemistry
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0

Answer:

D po ayan po ang sagot ko salamat po

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Near Cozumel, Mexico, a scuba diver goes down 60 ft to look at the sea creatures. As she descends, the air pressure increases. W
Rudik [331]

Answer: Boyle's Law

Explanation:

Boyle's Law which is also called Mariotte's law was formulated by physicist Robert Boyle in 1662.

It posits that the pressure (p) of a given quantity of gas varies inversely with its volume (v) at constant temperature.

As the Scuba Diver went deeper, the volume of air dropped so the pressure increased.

Please do react or comment to the answer if you have any issues or if you feel like this helped you so we can help others as well. Thank you.

5 0
3 years ago
Suppose that, from measurements in a microscope, you determine that a certain layer of graphene covers an area of 1.50μm2. Conve
Alex73 [517]
The answer is 1.5*10^-12 square meters. For a detailed calculation, please refer to the attachment.
Download docx
7 0
3 years ago
Which compound allows the earth to retain heat from the sun?
Anastaziya [24]

Answer:

D) Carbon Dioxide

Explanation:

Carbon is a greenhouse gas that traps heat.

Carbon is in Carbon Dioxide **Obviouslyyy lol

5 0
3 years ago
An impurity sometimes found in Ca₃(PO₄)₂ is Fe₂O₃, which is removed during the production of phosphorus as ferrophosphorus (Fe₂P
Citrus2011 [14]

This impurity is troubling from an economic standpoint because it lead to decrease in the yield of phosphorus

  • Ferrophosphorus is a byproduct of phosphorus production in submerged-arc furnaces , by their reduction with carbon. It is formed from the iron oxide impurities.
  • Iron impurities present in the calcium phosphate will be precipitated out as the iron phosphate which eventually will lead to the decrease in the yield of phosphorous during the production of phosphorous.

Thus we can conclude that Fe₂P causes decrease in yield

Learn more about production of phosphorus at brainly.com/question/13337198

#SPJ4

6 0
1 year ago
When 0.0901 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. I
Alexus [3.1K]

Answer:

The heat of combustion for the unknown hydrocarbon is -29.87 kJ/mol

Explanation:

Heat capacity of the bomb calorimeter = C = 1.229 kJ/°C

Change in temperature of the bomb calorimeter = ΔT = 2.19°C

Heat absorbed by bomb calorimeter = Q

Q=C\times \Delta T

Q=1.229 kJ/^oC\times 2.19^oC=2,692 kJ

Moles of hydrocarbon burned in calorimeter = 0.0901 mol

Heat released on combustion = Q' = -Q = -2,692 kJ

The heat of combustion for the unknown hydrocarbon :

\frac{Q'}{0.090 mol}=\frac{-2,692 kJ}{0.0901 mol}=-29.87 kJ/mol

6 0
3 years ago
Read 2 more answers
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