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3 years ago

How many grams of fluorine must be reacted with excess lithium iodide to produce 10.0 grams of lithium fluoride?

Chemistry

1 answer:

rewona [7]3 years ago

8 0

Answer:
7.32 g of F₂

Solution:
The equation is as follow,

2 LiI + F₂ → 2 LiF + I₂

According to equation,

51.88 g (2 mole) of LiF is produced from = 37.99 g (1 mole) F₂
So,
10 g of LiF will be produced by = X g of F₂

Solving for X,
X = (10 g × 37.99 g) ÷ 51.88 g

X = 7.32 g of F₂

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3 A soil has 70% sand, 20% silt

Kisachek [45]

Today, as part of the series of posts on soils, we are going to look at ‘soil texture’. Soil forms the basis for all life but it’s important to know about its mineral constitution as well as its biological profile.

Texture refers to the ‘feel’ of the soil. This is affected by the constituent materials found within it, specifically sand, silt and clay particles. A coarse sand will feel gritty but a wet clay will feel heavy and sticky. The texture of a soil has a direct impact on the way the soil reacts to certain environmental conditions – for example, towards drought or heavy rain (with sandy soils more freely draining).

There is a big difference in the size of the different particles.

Coarse sand = diameter 2-0.2mm

Fine sand = diameter 0.2-0.02mm

Silt = diameter 0.02-0.002mm

Clay = diameter less than 0.002mm

Note how the clay particles are much smaller than the sand particles – this is important as it means the total surface area of a clay soil is much greater and so the capacity to hold water is also much greater.

Between the sand, silt and clay particles there are lots of pores. In fact a soil as a whole is generally 45% mineral, 5% organic matter (depending on the soil) and 50% pore space through which air and water can pass.

Sand –

Made up of weathered primary rock minerals.

The particles are irregular in outline.

They are large and so do not pack together easily.

Large pore spaces in between.

Air gets in very easily and water flows rapidly through it.

Silt –

7 0

3 years ago

A molecule of acetone and a molecule of propyl aldehyde are both made from 3 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom.

TEA [102]

Explanation:

The structures of both acetone and propanal are shown below:

In the formula of propanal there is -CHO functional group at the end.

In acetone -CO- group is present in the middle that is on the second carbon.

The molecular formula is C3H6O.

Both have same molecular formula but different structural formulas.

7 0

3 years ago

Is this statement true or false?

Snezhnost [94]

The correct answer is False.

5 0

2 years ago

Read 2 more answers

How many moles of CO2 are emitted into the atmosphere when 22.1 g C8H18 is burned

ANTONII [103]

Answer:

1.552 moles

Explanation:

First, we'll begin by writing a balanced equation for the reaction showing how C8H18 is burn in air to produce CO2.

This is illustrated below:

2C8H18 + 25O2 -> 16CO2 + 18H2O

Next, let us calculate the number of mole of C8H18 present in 22.1g of C8H18. This is illustrated below:

Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol

Mass of C8H18 = 22.1g

Mole of C8H18 =..?

Number of mole = Mass /Molar Mass

Mole of C8H18 = 22.1/144

Mole of C8H18 = 0.194 mole

From the balanced equation above,

2 moles of C8H18 produced 16 moles of CO2.

Therefore, 0.194 mole of C8H18 will produce = (0.194x16)/2 = 1.552 moles of CO2.

Therefore, 1.552 moles of CO2 are emitted into the atmosphere when 22.1 g C8H18 is burned

8 0

3 years ago

titration 25.0 ml of 3.4 x 10^ -3 M of Ba(OH) Neutralize 16.6 mL of HCL solution. What is the molarity of HCL solution?

marusya05 [52]

What we are give: Concentration of base (CB) = 3.4 × $10^{-3}$
Then convert all volume in ml to L.
Volume of base (VB) 25.0ml = 0.025L
Volume of acid (VA) 16.6ml = 0.0166L
Now that we have everything we use the formula CAVA=CBVB.
Make 'CA' the subject then solve.
CA= $\frac{CBVB}{VA}$

8 0

3 years ago