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3 years ago

How many grams of fluorine must be reacted with excess lithium iodide to produce 10.0 grams of lithium fluoride?

Chemistry

1 answer:

rewona [7]3 years ago

8 0

Answer:
7.32 g of F₂

Solution:
The equation is as follow,

2 LiI + F₂ → 2 LiF + I₂

According to equation,

51.88 g (2 mole) of LiF is produced from = 37.99 g (1 mole) F₂
So,
10 g of LiF will be produced by = X g of F₂

Solving for X,
X = (10 g × 37.99 g) ÷ 51.88 g

X = 7.32 g of F₂

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What is the change in density if a sample goes from 3.21 g/L to 5.43 g/mL?

Step2247 [10]

Answer:

$\Delta \rho =2.22 g/mL$

Explanation:

Hello,

In this case, since a change in science is widely known to be considered as a subtraction between the the final and initial values of two measured variables and is represented via Δ, here the final density is 5.43 g/mL and the initial one was 3.21 g/mL, therefore, the change in density is:

$\Delta \rho=\rho _f-\rho _i\\ \\\Delta \rho=5.43g/mL-3.21g/mL\\\\\Delta \rho =2.22 g/mL$

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2 years ago

Сульфат железа (II) окисляется в кислой среде перманганатом калия до Fe2(SO4)3, т.е. окисляется. Запишите и приравняйте уравнени

SOVA2 [1]

Answer:

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5 0

2 years ago

Draw a bond-line structure for CH3CH2O(CH2)2CH(CH3)2. Include Lone Pairs in your answer.

mash [69]

Answer:

See explanation and image attached

Explanation:

A bond line structure refers to any structure of a covalent molecule wherein the covalent bonds present in the molecule are represented with a single line for each level of bond order.

The bond-line structure of CH3CH2O(CH2)2CH(CH3)2 has been shown in the image attached. We know that oxygen has a lone pair of electrons and this has been clearly shown also in the image attached.

7 0

2 years ago

Which of the following is NOT the same?

Inessa [10]

All are the same. It equals to the same thing.

4 0

2 years ago

Read 2 more answers

The car wit fastest acceleration is the tempest. it has an acceleration of 6.1 m/s. suppose the car accelerates from rest to a f

ziro4ka [17]

Given:

Initial velocity (v1) = 0 m/s

Final velocity (v2) = 30 m/s

Acceleration (a) = 6.1 m/s2

To determine:

The time (t) taken to reach the final speed

Explanation:

Use the relation:

Acceleration (a) = [final velocity(v2) - initial velocity (v1)]/time (t)

t = (v2-v1)/a = 30-0/6.1 = 4.92 s

Ans: Time taken is around 4.9 s

3 0

3 years ago