(2/3)x^2 -6x + 15 = 0
Using the quadratic formula:
x = [-b +-sq root(b^2 - 4 *a*c)] / 2a
x= [--6 +-sq root(36 -4*(2/3)*15] / 2*(2/3)
x= [6 +-sq root 36 -40] / (4/3)
x1 = 4.5 + (2i / (4/3))
x1 = 4.5 + 1.5i
x2 = 4.5 - (2i / (4/3))
x2 = 4.5 - 1.5i
Answer:
<h2>i) 3</h2><h2>ii) 5</h2>
Step-by-step explanation:
Let H be the set of students who play Hokey
V be the set of students who play Volleyball
S be the set of students who play Soccer
======================================
card(volleyball only) = card(V) - [card(V∩H∩S) + card(V∩H only) + card(V∩S only)]
= 73 - [50 + (58-50) + (62-50)]
= 73 - [50 + 8 + 12]
= 73 - 70
= 3
………………………………………………
Card(Hokey only) = 100 - [3 + 8 + 50 + 10 + 12 + 12]
= 100 - 95
= 5
…………………
<u><em>Note</em></u> :
A Venn diagram might be helpful in such case.
Answer:
x=3
Step-by-step explanation:
6 10
---------- = ------------
6+x 15
using cross products
6 * 15 = 10 * (6+x)
90 = 60+10x
subtract 60 from each side
90-60 = 60+10x-60
30 = 10x
divide by 10
30/10 = 10x/10
3=x
1. false because it has only 2 triangular faces
2. true
3. true
4. i think its false, it has four
5.