What is generally true about the particles in a liquid? a. They are closer together and have lower energy than the particles in
2 answers:
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Answer:
Choice A. 0.50 g.
Explanation:
According to the question, the reaction here converts
- caesium (cesium) carbonate and
- hydrogen bromide
to
- cesium bromide,
- carbon dioxide, and
- water.
By the Law of Conservation of Mass, matter can neither be created nor destroyed in a chemical reaction. (Shrestha et. al, Introductory & GOB Chemistry, Chemistry Libretexts, 2019.)
In other words, the mass of the reactants, combined, shall be the same as the mass of the products, combined.
What's the mass of the reactants?
.
What's the mass of the products?
Let represent the mass of carbon dioxide produced in this reaction.
The mass of the products will be:
.
The two masses shall be equal. That is:
.
.
In other words, by the Law of Conservation of Mass, the mass of carbon dioxide produced in this reaction will be .
Answer:
<u>= 48.077 kcal </u>
Explanation:
The balanced equation is :
Since the stoichiometric coefficient of Na2O = 1 hence its heat is
<u>-120 Kcal/mol</u> rather -120 Kcal only.
This means when 1 mole of the Na2O is burned , then 120 kcal of energy is released .
Molar mass of Na2O = 2(mass of Na) + 1(mass of O)
= 2(22.98)+16
=61.97 gram/mol
Molar mass = mass of the substance in grams present in 1 mole of it.
In 1 mole of Na2O , 61.97 gram of it is present.
Hence
61.97 gram of Na2O = -120 Kcal of heat is released
1 gram of Na2O =
So,
24.8 gram of Na2O will produce,
= -48.077 kcal of heat
You can also proceed through mole concept:
Calculate number of moles in 24.8 gram Na2O
Moles of Na2O = 24.08/61.9 = 0.4007 moles
So these many moles will produces:
0.4007 x 120
=-48.07