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Semmy [17]
3 years ago
7

A company is expanding its building area from 11,000 square feet to 14,740 square feet. What is the percentage increase of the a

rea
of the building space?​

A. 66%
B. 37.4%
C. 3.4%
D. 34%
Mathematics
1 answer:
svlad2 [7]3 years ago
6 0

Option D

The percentage increase of the area  of the building space is 34 %

<em><u>Solution:</u></em>

A company is expanding its building area from 11,000 square feet to 14,740 square feet

To find: Percentage Increase

<em><u>The percent increase is given by formula:</u></em>

\text{Percent increase } = \frac{\text{Final value - Initial value}}{\text{Initial value}} \times 100

From given,

Initial value = 11000

Final value = 14740

<em><u>Substituting we get,</u></em>

Percent\ Increase = \frac{14740-11000}{11000} \times 100\\\\Percent\ Increase = \frac{3740}{110}\\\\Percent\ Increase = 34

Thus percentage increase of the area  of the building space is 34 %

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Helga [31]

Answer:

2.50 dollars.

Step-by-step explanation:

Given:

Will and his friends buy a large salad to share and several slices of pizza, p.

The graph given shows the total cost for lunch, c and slices of pizza,p.

p is marked horizontally, and c vertically.

Observing the points marked we find that for every increase of one slice of pizza, the cost i.e. c on vertical line increases by 0.50 times vertical grid.

Since each grid equals 5 dollars vertically, we find 1/2 grid increase is equal to increase of 1/2(5 ) =2.50 dollars.

Thus for increase of one slice of pizza, 2.50 dollars cost is increased.

5 0
3 years ago
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Compare the decimals 7,231.60 and 7,231.6. Which comparison is correct? A. 7,231.60 &lt; 7,231.6 B. 7,231.60 = 7,231.6 C. 7,231.
Ilia_Sergeevich [38]
B. 7,231.60 = 7,231.6
3 0
4 years ago
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A 9<br> B 18<br> C 4.5<br> D 19<br><br> Thanks
irina1246 [14]

Answer:

The answer is C. 4.5. Hope that helps.

Step-by-step explanation:

7 0
4 years ago
I need help on #7<br> Please show your work
givi [52]

The area of the given square pyramid is:

total area = 1,100 inches squared.

<h3 /><h3>How to get the area of the pyramid?</h3>

On the second image, we can see that the pyramid is conformed of a square base and 3 triangles.

To get the surface area of the pyramid, we can just get the area of each of these simpler parts.

The base is a square of 22 in by 22 in, then the area of the base is:

B = (22in)*(22 in)  = 484 in^2

For each triangle, the area will be:

A = (base side)*(height)/2

A = (22in)*(14in)/2 = 154 in^2

And we have 4 of these triangles, then the total area of the pyramid will be:

total area = B + 4*A = 484in^2 + 4*(154 in^2) = 1,100 in^2

If you want to learn more about square pyramids:

brainly.com/question/22744289

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3 0
1 year ago
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
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