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2 years ago

Write down short notes on:c. Power

1 answer:

4 0

Answer: In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.

Explanation: SI unit: watt (W)

In SI base units: kg⋅m2⋅s−3

Derivations from other quantities: P = E/t; P = F...

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3m/s for 12 seconds how dar would he walk

Sunny_sXe [5.5K]

I think 36m/12s because 3×12 =36

4 0

2 years ago

On Earth, 1 kg = 9.8 N = 2.2 lbs. On the Moon, 1 kg = 1.6 N = 0.37 lbs. Use these relationships to answer the following question

romanna [79]

Answer:

(a) 490 N on earth

(b) 80 N on earth

(d) 270.27 kg on moon

Explanation:

We have given 1 kg = 9.8 N = 2.2 lbs on earth

And 1 kg = 1.6 N = 0.37 lbs on moon

(a) We have given mass of the person m = 50 kg

As it is given that 1 kg = 9.8 N

So 50 kg = 50×9.8 =490 N

(b) Mass of the person on moon = 50 kg

As it is given that on moon 1 kg = 1.6 N

So 50 kg = 50×1.6 = 80 N

As it is given that 1 kg = 2.2 lbs on earth

So 100 lbs = 45.4545 kg

(d) We have given weight of the person on moon = 100 lbs

As it is given that 1 kg = 0.37 lbs

So 100 lbs $\frac{100}{0.37}=270.27kg$

8 0

3 years ago

What is the proper battery cable connection when jumping two automotive batteries? (a) negative to negative / positive to positi

Vladimir [108]

The proper battery cable connection when jumping two automotive batteries is : (a) negative to negative / positive to positive.

Connect the red (positive) cable from the car with the bad battery to the red (positive) on the good battery. 

Then connect the black (negative) from the good battery to a grounding point on the other car which should be tightened and metal should be clean.

Once the car with bad battery has started, the removal of the cable should be in the opposite order. The Red (positive) which was the the First Cable to go on should be the last cable to be taken off.

3 0

3 years ago

The moon Phobos orbits Mars

podryga [215]

Explanation:

For a circular orbit v= $\sqrt{\frac{G.m}{r} }$ with G = 6.6742 × $10^{-11}$

Given m = 6.42 x 10^23 kg and r=9.38 x 10^6 m

=> v = 2137.3 m/s

I hope this is the correct way to solve

3 0

2 years ago

The metal gold crystallizes in a face centered cubic unit cell with one atom per lattice point. When X-rays with λ = 1.436 Å are

Umnica [9.8K]

Answer:

r = 1.45 Å

Explanation:

given,

λ = 1.436 Å

θ = 20.62°

d = a

n = 2

metal gold crystallizes in a face centered cubic unit cell

Radius of the gold atom = ?

using Bragg's Law

n λ = 2 d sin θ

2 x 1.436 Å = 2 a sin 20.62°

a = 4.077 Å

We know relation of radius for face centered cubic unit cell

$a = \dfrac{4r}{\sqrt{2}}$

$4.077= \dfrac{4\times r}{\sqrt{2}}$

r = 1.45 Å

the radius of a(n) gold atom. is equal to 1.45 Å

7 0

3 years ago

Write down short notes on:c. Power​

Write down short notes on:c. Power