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mafiozo [28]
3 years ago
10

Write down short notes on:c. Power​

Physics
1 answer:
Fudgin [204]3 years ago
4 0

Answer: In the International System of Units, the unit of power is the watt, equal to one joule per second. In older works, power is sometimes called activity. Power is a scalar quantity.

Explanation: SI unit: watt (W)

In SI base units: kg⋅m2⋅s−3

Derivations from other quantities: P = E/t; P = F...

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A car is traveling in a uniform circular motion on a section of road whose radius is r. The road is slippery, and the car is jus
Basile [38]

Answer:

a)r' = 4 r

b)V=\sqrt{\mu rg}  

Explanation:

Given that car is moving with uniform speed.

At the verge of sliding

Friction force = Force due to circular motion

\mu mg=\dfrac{mV^2}{r}

So we can say that

V=\sqrt{\mu rg}          -----1

Where is the coefficient of friction

r is the radius of circular path

V is the velocity of car

a)

if the car speed become double

It means that new speed of car =2V

lets tale new radius of circular path is r'

2V=\sqrt{\mu r'g}                ---------2

From equation 12 and 2 we cay that

r' = 4 r

It means that we have to increase radius 4 times to avoid sliding

b)

V=\sqrt{\mu rg}  

In the above expression there is no any terms of mass ,it means that sliding speed does not depends on the weight of car.

So the sliding speed will remain same.

V=\sqrt{\mu rg}  

4 0
3 years ago
Your're sailing a boat from spain west to florida. which winds would you use?
timurjin [86]
The wind you would use to travel from Spain west to Florida are The Trade Winds
6 0
3 years ago
A device that uses electricity and magnetism to create motion is called a (motor magnet generator) . In a reverse process, a dev
Tems11 [23]

the answers are a. and c.

I hope I help you out!

6 0
3 years ago
Read 2 more answers
A playground merry-go-round has a mass of 115 kg and a radius of 2.50 m and it is rotating with an angular velocity of 0.520 rev
tatuchka [14]

Answer:

W_f = 2.319 rad/s

Explanation:

For answer this we will use the law of the conservation of the angular momentum.

L_i = L_f

so:

I_mW_m = I_sW_f

where I_m is the moment of inertia of the merry-go-round, W_m is the initial angular velocity of the merry-go-round, I_s is the moment of inertia of the merry-go-round and the child together and W_f is the final angular velocity.

First, we will find the moment of inertia of the merry-go-round using:

I = \frac{1}{2}M_mR^2

I = \frac{1}{2}(115 kg)(2.5m)^2

I = 359.375 kg*m^2

Where M_m is the mass and R is the radio of the merry-go-round

Second, we will change the initial angular velocity to rad/s as:

W = 0.520*2\pi rad/s

W = 3.2672 rad/s

Third, we will find the moment of inertia of both after the collision:

I_s = \frac{1}{2}M_mR^2+mR^2

I_s = \frac{1}{2}(115kg)(2.5m)^2+(23.5kg)(2.5m)^2

I_s = 506.25kg*m^2

Finally we replace all the data:

(359.375)(3.2672) = (506.25)W_f

Solving for W_f:

W_f = 2.319 rad/s

7 0
3 years ago
What are 2 ways electromagnets are used
lisabon 2012 [21]
Electromagnets are used for various purposes but I fathom in this instance, the questioner is asking about how electromagnetics can be used to attraction or repulsion.
Example, electromagnets are used for attraction in cranes which attach them to containers in order to lift them.
Meanwhile, Maglev trains use electromagnets repulsive properties.
4 0
3 years ago
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