Question

You have 5 Red Marbles, 4 Green Marbles, and 3 Blue Marbles in a Bowl. You randomly pick 4 marbles from the bowl (without replacing any marbles into the bowl). You carry the 4 marbles into another room. What is the probability you chose EXACTLY 2 Red, 1 Green, and 1 Blue IN ANY ORDER?

Answer 1

Answer:

2%

Step-by-step explanation:

In this case each one is an independent event, therefore, the multiplication of each one would be the final probability

We have 5 Red Marbles, 4 Green Marbles, and 3 Blue Marbles, that is, there are 5 + 4 + 3 12 Marbles in total.

Now if I draw a red one, the probability would be: 5/12

When drawing another red, the probability would be: 4/11

When taking the green: 4/10

When removing the blue: 3/9

Finally, the final probability is:

P = (5/12) * (4/11) * (4/10) * (3/9)

P = 0.020

In other words, the probability of this happening is 2%