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Lady_Fox [76]
3 years ago
9

A 60.0-kg ball of clay is tossed vertically in the air with an initial speed of 4.60 m/s. Ignoring air resistance, what is the c

hange in its potential energy when it reaches its highest point?
Physics
1 answer:
Misha Larkins [42]3 years ago
7 0

Answer:

<em>the change in potential energy when it reaches the highest height = 634.8 J</em>

Explanation:

<em>Potential Energy</em>: This is the energy a body posses due to position.

From the law of conservation of energy,

At the highest point and lowest points, potential energy is converted to kinetic energy

I.e

Ek = Ek

Where Ek = potential energy, Ep = potential energy

Ep₁ = 1/2mu²  (potential energy at the lowest point)................ Equation 1

Ep₂ = 1/2mv² (potential energy at the highest point)............. Equation 2

ΔEp = Ep₂ - Ep₁ = 1/2mu² - 1/2mv²........................ Equation 3

Where ΔEp = change in potential energy, m = mass of the ball of clay, v = final velocity of the ball of clay, u = initial velocity of the ball of clay

Given: <em>m= 60 kg, u = 4.6 m/s v = 0 ( velocity at the maximum height)</em>

<em>Substituting these values into equation 3</em>

ΔEp = 1/2×60×4.6 - 1/2×60×0²

ΔEp = 30×21.16 - 0

<em>ΔEp = 634.8 J.</em>

<em>Therefore the change in potential energy when it reaches the highest height = 634.8 J</em>

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lara [203]

Answer:

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Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces [N]

m = mass = 14 [kg]

a = acceleration = 6 [m/s²]

F = 14*6\\F = 84 [N]

In the second part of this problem we must find the work done, where the work in physics is known as the product of force by distance, it is important to make it clear that force must be applied in the direction of movement.

W = F*d

where:

W = work [J]

F = force = 84 [N]

d = displaciment = 40 [m]

W = 84*40\\W = 3360 [J]

Finally, the power can be calculated by the relationship between the work performed in a given time interval.

P=W/t\\

where:

P = power [W]

W = work = 3360 [J]

t = time = 100 [s]

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P=3360/100\\P=33.6[W]

The power is given in watts

3 0
3 years ago
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2m/s

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Its average speed during that time is  (1/2) (10 + 0) = 5 m/s .

At an average speed of 5 m/s for 1.02 sec,
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