Answer:
16 m/s.
Explanation:
The following data were obtained from the question:
Mass of truck = 5000 Kg
Velocity of truck = 8 m/s
Mass of car = 2500 kg
Velocity of car =..?
Next, we shall determine the momentum of the truck. This can be obtained as follow:
Mass of truck = 5000 Kg
Velocity of truck = 8 m/s
Momentum of truck =.?
Momentum = mass × velocity
Momentum = 5000 × 8
Momentum of the truck = 40000 Kg.m/s
Finally, we shall determine the velocity of the car as follow:
From the question given above, we were told that the car and truck has the same momentum.
This implies that:
Momentum of the truck = momentum of car = 40000 Kg.m/s
Thus, the velocity of the car can be obtained as shown below:
Mass of car = 2500 kg
Momentum of the car = 40000 Kg.m/s
Velocity of car =..?
Momentum = mass × velocity
40000 = 2500 × velocity
Divide both side by 2500
Velocity = 40000/2500
Velocity = 16 m/s
Therefore, the velocity of the car is 16 m/s.
I’m pretty sure it just wants you to list the property’s meaning the material and density
Let the rescue boat starts at an angle theta with the North
now its velocity towards East is given as
now in some time "t" it will catch the boy
so we will have
also we have
now we have
by solving above we got
D.Radiant energy does not require a medium through which to travel.
Answer:
x = 0.75801 = 75.801%
T_2 = 72..78 degree F
Explanation:
From superheated R 134 a properties table
At 200 lb/in^2 and 200 degree F
steady flow energy equation is givena s
At 90 lb/in2 Tsat = 72.78 degree F
hfg = 77.345 Btu/lbm
h = hf + x hfg
solving for x we get
x = 0.75801 = 75.801%
