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worty [1.4K]
2 years ago
10

What is the displacement (in miles, with direction) from the Aquarium to the Cemetery?

Physics
1 answer:
irina [24]2 years ago
3 0

Look up "Everything You Need To Know About Math In One Big Fat Notebook pdf." It's the best thing I've ever been given, I have it with me in math class all the time and I've aced every test. I have it with me right now and it has everything I've ever been taught about math in it so it might help you.

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A vector has an x component of 25.0 units and a y
sammy [17]
Here is the answer to your question

8 0
3 years ago
A 1,000 kg car is travelling at 6.5 m/s to the North. A 3,500 kg truck is travelling South at the same velocity. What is the tot
Molodets [167]

Answer:

16250 kgm/s due south

Explanation:

Applying,

M = mv................. Equation 1

Where M = momentum, m = mass, v = velocity.

From the car,

Given: m = 1000 kg, v = 6.5 m/s

Substitute these values into equation 1

M = 1000(6.5)

M = 6500 kgm/s

For the truck,

Given: m = 3500 kg, v = 6.5 m/s

Substitute these values into equation 1

M' = 3500(6.5)

M' = 22750 kgm/s.

Assuming South to be negative direction,

From the question,

Total momentum of the two vehicles = (6500-22750)

Total momentum of the two vehicles = -16250 kgm/s

Hence the total momentum of the two vehicles is 16250 kgm/s due south

3 0
2 years ago
When air resistance balances the weight of an object that is falling, the velocity _____.
miskamm [114]
Decreases. Air resistance will slow a falling object to its terminal velocity, placing a limit on its acceleration. 
5 0
3 years ago
How much mass would pizza dough have after you flatten it
mars1129 [50]

Answer:

the answer is that the dough has the same mass before and after it was flattened

3 0
2 years ago
Read 2 more answers
An airplane starts from A and flies to B at a constant speed. After reaching B it returns to A at the same speed. There was no w
Dafna1 [17]

Answer:

When there is wind it takes longer

Explanation:

With no wind, the round trip time is

t_1=\frac{d}{v}+\frac{d}{v}=\frac{2d}{v}

When we have a constant wind speed w

t_2=\frac{d}{v-w} +\frac{d}{v+w} =\frac{2vd}{v^{2} -w^{2}}

comparing the reciprocal times;

\frac{1}{t_2}=\frac{v^{2}-w^{2} }{2vd}=\frac{v}{2d}-\frac{w^{2}}{2vd}   \leq \frac{v}{2d}=\frac{1}{t_1}

This means that t1 is smaller than t2, ergo, it takes longer with wind

4 0
2 years ago
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