Answer:
No.
Explanation:
The average distance to the center is over 6300km.
Answer:
pH is 7.60
Explanation:
Let's think the equations:
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
As every weak acid, we make an equilbrium
The salt is dissociated in solution
NaClO → Na⁺ + ClO⁻
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
Initially 0.3m 0.35m
We have the moles of acid, and the moles of conjugate base.
Reacts x X X
Some amount has reacted, so I obtained (in equilibrium) the moles of base + that amount, and the same amount for H₃O⁺ (ratio is 1:1)
HClO + H₂O ⇄ ClO⁻ + H₃O⁺
0.3 - x 0.35 + x x
Let's make the expression for Ka
Ka = [ClO⁻] . [H₃O⁺] / [HClO]
(we don't add water, because it is included in Ka)
2.9x10⁻⁸ = (0.35+x).x / (0.3-x)
Ka is in order of 10⁻⁸, I can assume that 0.3-x is 0.3 and 0.35 +x =0.3
2.9x10⁻⁸ = (0.35)x / (0.3)
(2.9x10⁻⁸ . 0.3) /0.35 = x
2.48x10⁻⁸ = x
This is [H₃O⁺]
For pH = - log [H₃O⁺]
pH = 7.60
Answer: -
2.5 moles of calcium atoms are in 2.5 moles of calcium carbonate CaCO₃
Explanation: -
In order to solve such types of problems, the first step would be to write the chemical formula of the compound.
The chemical formula of calcium carbonate = CaCO₃
The chemical symbol of Calcium is Ca.
From the formula of calcium carbonate we can see that
1 mole of CaCO₃ has 1 mole of Ca
2.5 mole of CaCO₃ has 
= 2.5 mol of Ca.
∴2.5 moles of calcium atoms are in 2.5 moles of calcium carbonate CaCO₃
Express the oxidation state numerically (e.g., +1).
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Ions
In an ion, the sum of the oxidation states is equal to the overall ionic charge. Note that the sign of the oxidation states and the number of atoms associated with each oxidation state must be considered. In OH−, for example, the oxygen atom has an oxidation state of −2 and the hydrogen atom has an oxidation state of +1, for a total of (−2)+(+1)=−1.
Part C
What is the oxidation state of an individual phosphorus atom in PO33−?
Express the oxidation state numerically (e.g., +1).
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Part D
What is the oxidation state of each individual carbon atom in C2O42−?
Express the oxidation state numerically (e.g., +1).
Answer:
5.42 mol
Explanation:
To find moles, divide the given mass by the compounds molar mass. To find the molar mass of the compound, add of the masses of each individual component:
Molar mass of NaNCO3 = Na + N + C + (O x 3)
Molar mass of NaNCO3 = 23 + 14 + 12 + (16 x 3)
Molar mass of NaNCO3 = 97 g/mol
Moles = mass / molar mass
Moles = 526 g / 97 g/mol
Moles = 5.42 mol
