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3 years ago

What other elements does zinc bond with?

Chemistry

1 answer:

Angelina_Jolie [31]3 years ago

4 0

Answer:

oxygen and other non-metals

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How many electrons are shared in the Lewis structure

Diano4ka-milaya [45]

Hey there,

Answer:

4 valence electrons.

Hope this helps :D

<em>~Top☺</em>

3 0

3 years ago

________ exercise strengthens skeletal muscle, and ________ exercise strengthens skeletal and cardiac muscle.

valentinak56 [21]

Answer:

6 0

3 years ago

Suppose that a certain fortunate person has a net worth of $77.0 billion ($). If her stock has a good year and gains $3.20 billi

marissa [1.9K]

Answer:

New net worth to three significant figures = $80.2 billion

Dollars are given to charity = $100,250,000

Explanation:

Net worth = $77.0 billion

stock Gains = $3.20 billion

New net worth = $77.0 billion + $3.20 billion = $80.20 billion

New net worth to three significant figures = $80.2 billion

One-eighth of a percent = (1/8 x 1) / 100 = 0.00125

Dollars are given to charity = 0.00125 X $80.2 billion = $100,250,000

$80,200,000,000/100 = $802,000,000

3 0

3 years ago

A doorknob makes it easier for you to open doors because it is what type of simple machine?

vagabundo [1.1K]

Answer: Wheel and Axle

Both of these work together to form a simple machine. You can't have one without the other.

If you try to turn just the axle itself, then you'll find it takes a lot of work. This is because the inertia of the axle wants to keep the object at rest. Also, you won't have a lot of torque due to the small radius compared to what a doorknob can offer.

Using a doorknob is like putting a (steering) wheel on an axle. This increases the radius and therefore increases the torque. You put in less work into the system and get more out of it.

5 0

3 years ago

You are provided with a stock solution with a concentration of 1.0x10-5 M. You will be using this to make two standard solutions

artcher [175]

Answer:

1. V₁ = 2.0 mL

2. V₁ = 2.5 mL

Explanation:

<em>You are provided with a stock solution with a concentration of 1.0 × 10⁻⁵ M. You will be using this to make two standard solutions via serial dilution.</em>

To calculate the volume required (V₁) in each dilution we will use the dilution rule.

C₁ . V₁ = C₂ . V₂

where,

C are the concentrations

V are the volumes

1 refers to the initial state

2 refers to the final state

<em>1. Perform calculations to determine the volume of the 1.0 × 10⁻⁵ M stock solution needed to prepare 10.0 mL of a 2.0 × 10⁻⁶ M solution.</em>

C₁ . V₁ = C₂ . V₂

(1.0 × 10⁻⁵ M) . V₁ = (2.0 × 10⁻⁶ M) . 10.0 mL

V₁ = 2.0 mL

<em>2. Perform calculations to determine the volume of the 2.0 × 10⁻⁶ M solution needed to prepare 10.0 mL of a 5.0 × 10⁻⁷ M solution.</em>

C₁ . V₁ = C₂ . V₂

(2.0 × 10⁻⁶ M) . V₁ = (5.0 × 10⁻⁷ M) . 10.0 mL

V₁ = 2.5 mL

8 0

3 years ago