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Ulleksa [173]
3 years ago
9

Uhu khanay sai kia hota hai

Chemistry
1 answer:
trapecia [35]3 years ago
3 0
Pardon me uh hmm interesting
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The ka values for several weak acids are given below. which acid (and its conjugate base) would be the best buffer at ph = 8.0?
Pie
One of the best buffer choice for pH = 8.0 is Tris with Ka value of  6.3 x 10^-9.

To support this answer, we first calculate for the pKa value as the negative logarithm of the Ka value: 
     pKa = -log Ka

For Tris, which is an abbreviation for 2-Amino-2-hydroxymethyl-propane-1,3 -diol and has a Ka value of 6.3 x 10^-9, the pKa is
     pKa = -log Ka
            = -log (6.3x10^-9)
            = 8.2

We know that buffers work best when pH is equal to pKa:
     pKa = 8.2 = pH 

Therefore Tris would be a best buffer at pH = 8.0.
7 0
4 years ago
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Carbohydrates, more commonly known as sugars, are made up of carbon, oxygen, and hydrogen atoms. the smallest unit of a carbohyd
lukranit [14]
I believe the statement above is true. <span>A </span>carbohydrate<span> is a </span>biological molecule<span> consisting of </span>carbon<span> (C), </span>hydrogen<span> (H) and </span>oxygen<span> (O) atoms, usually with a hydrogen–oxygen </span>atom ratio of 2:1. <span>When a </span>carbohydrate<span> is broken into its component sugar molecules by </span>hydrolysis<span> (e.g. sucrose being broken down into glucose and fructose), this is termed saccharification.</span>
3 0
3 years ago
Is density physical or chemical
stepan [7]
Density is a physical
6 0
3 years ago
¿Cuáles son ejemplos de elementos químicos que pertenecen al grupo de los gases nobles o gases raros?
Aliun [14]

Answer:

traducir al español esa es la respuesta

自分の仕事をする

Explanation:

5 0
3 years ago
Denver, Colorado (altitude above sea level is 5,280 ft) has an atmospheric pressure of 633. mm Hg. Calculate the boiling point o
Fed [463]

Answer:

T2 = 94.6 C

Explanation:

Use Clausius-Clayperyon equation.

ln P1/P2 = ∆Hvap/R (1/T2 - 1/T1) where R = 8.314 J/mol-K and T is in degrees K

P1 = 760 mmHg

P2 = 630 mmHg  

T1 = 373 K

T2 = ?

∆Hvap = 40.7 kJ/mole

R = 0.008314 kJ/mole-K (NOTE: change R to units of kJ)

Plug in and solve for T2

ln 760 mmHg/630 mmHg = 40.7 kJ/mole (1/T2 - 1/373K)

T2 = 367.74 K = 94.6 C

8 0
3 years ago
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