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3 years ago

Why is the brcl molecules polar??

Chemistry

2 answers:

Dahasolnce [82]3 years ago

6 0

The electronegativity value of Br and Cl is 2.8 and 3.0 respectively.

The electrinegativity difference in the Br-Cl bond is 3.0 – 2.8 = 0.2

If the electronegativity difference is below 0.5 the covalent bind is nonpolar

If the electronegativity difference is between 0.5 and 2.0 the covalent bond is polar.

If the electronegativity difference is above 2.0 the bond is ionic

As the electronegativity difference is below 0.5 the Br-Cl covalent bond is nonpolar

tester [92]3 years ago

5 0

<span>Because there is a permanent dipole between the Br and Cl atom. The Cl atom has a higher electronegativity, so it will tend to pull the "shared" electrons formed in the bond to its pole, creating a permanent dipole and partial electron deficiency on the bromine atom.</span>

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2 years ago

A una mezcla de 300g, formada con 60% P/P de Hierro y 40% P/P de Arena, se le adicionan 135g de Cobre y 2,77g de Aluminio. ¿Cuál

Svetllana [295]

Answer:

$\%P/P_{hierro}=41.1\%\\\\\%P/P_{arena}=24.4\%\\\\\%P/P_{cobre}=30.8\%\\\\\%P/P_{aluminio}=0.6\%$

Explanation:

¡Hola!

En este caso, dado que estamos tratando con problem sobre porcentaje peso/peso de hierro, arena, cobre y aluminio, primero debemos calcular la masa inicial de estos dos primeros en la mezcla original de acuerdo con:

$m_{hierro}=300g*0.60=180g\\\\m_{arena}=300*0.40=120g$

Ahora si podemos calcular la masa de la mezcla final como la suma de las masas de todos los constituyentes de la mezcla:

$m_T=180g+120g+135g+2.77g=437.77g$

Finalmente, podemos calcular los porcentajes P/P como se muestra a continuación:

$\%P/P_{hierro}=\frac{180g}{437.77g} *100\%=41.1\%\\\\\%P/P_{arena}=\frac{120g}{437.77g} *100\%=24.4\%\\\\\%P/P_{cobre}=\frac{135g}{437.77g} *100\%=30.8\%\\\\\%P/P_{aluminio}=\frac{g}{437.77g} *100\%=0.6\%$

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2 years ago

You guys I need help !

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Answer:

i think a as well but not sure

Explanation:

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2 years ago