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3 years ago

PLEASE HELP AND ILL GIVE 10 POINTS AND BRAINLIEST. ONLY ANSWER A, B, C, I

Mathematics

1 answer:

umka21 [38]3 years ago

3 0

Answer:

GIVE ME YOUR POINNTTSSSSSSSSSSSSSSSSSSSSSSSS

Step-by-step explanation:

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Area is 180,length is 1 1/4,what is the width

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180 is the area and the length is 1.25 so we need to find the width. We need to divide 180/1.25 which is 144.
144*1.25 is 180
The width is
144

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How to solve logarithmic equations as such

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$\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5$

$\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}$

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3 years ago

Write an equation in slope-intercept form for the line that satisfies the following condition.passes through (20, 1), parallel t

Dmitrij [34]

Slope-intercept form: y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

For lines to be parallel, they have to have the same slope.

y = 6x + 6 The slope of this line is 6, so the parallel line's slope is also 6.

Now that you know m = 6, substitute/plug it into the equation:

y = mx + b Plug in 6 for "m" in the equation

y = 6x + b To find "b", plug in the point (20, 1) into the equation

1 = 6(20) + b

1 = 120 + b Subtract 120 on both sides to get "b" by itself

1 - 120 = 120 - 120 + b

-119 = b Now that you know b = -119, plug it into the equation

y = 6x - 119

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3 years ago

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2 years ago

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Step-by-step explanation:

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