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Andrej [43]
3 years ago
5

What happens to the potential energy of an object when it is falls from a height? A. Its is lost. B. It is converted into anothe

r form, mainly thermal energy. C. It is converted into another form, mainly kinetic energy. D. It stays in the object.
Physics
2 answers:
erma4kov [3.2K]3 years ago
8 0

Answer:

<u><em>The answer is</em></u>: <u>C. It becomes another form, mainly kinetic energy.</u>

<u />

Explanation:

Potential energy <em>is that which has a body due to the height at which it is. </em>

<em>For example, a pot placed in a window at a certain height</em> has potential energy.

<em>When a body falls from a certain height, and if we despise friction with the air, what happens is</em><u><em> </em></u><u>that its potential energy is transformed into kinetic energy</u>.

<u><em>The answer is</em></u>: <u>C. It becomes another form, mainly kinetic energy.</u>

Damm [24]3 years ago
7 0

Answer:

C. It is converted into another form, mainly kinetic energy

Explanation:

Potential energy is energy available to be used in an object that isn't currently moving. When an object begins moving, potential energy becomes kinetic energy.

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The acceleration of a moving vehicles is 10 metre per second square what does it means ​
pochemuha

Answer:

Acceleration is the rate of change of velocity. What is commonly said as ‘ten meter per second squared’ can bee broken down into ‘ten meter per second per second.’ This gives us the true meaning of the term acceleration.

Just like ‘ten meter per second’ means increasing the displacement by ten meters every second, ‘ten meter per second per second’ means increasing the velocity by ten meters per second every second.

So, basically if you consider the case of a free fall motion, where ‘t’ stands for time and ‘v’ stand for velocity at that instant:

At,

t=0, v=0 m/s

t=1, v=0+10 m/s;

t=2, v=0+10+10 m/s;

t=3, v=0+10+10+10 m/s;

This can also be thought as a Arithmetic Progression where common difference ‘D’ is the acceleration(a), since it adds a 10 m/s to velocity every second and the first term ‘A’ stands for the initial velocity (u). Using this approach we can derive to the first equation of motion:

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To see if your results are reasonable, you can compare the final velocity of the stone as it falls down unwinding the wire from
pentagon [3]

Answer:

The velocity of the stone is 2.57 m/s.

Explanation:

Given that

Height = 0.337 m

We need to calculate the velocity of the stone

Using equation of motion

v^2-u^2=2gh

Where, v = velocity of stone

u = initial velocity

g = acceleration due to gravity

h = height

Put the value into the formula

v^2-0=2\times9.8\times 0.337

v=\sqrt{2\times9.8\times0.337}

v=2.57\ m/s

Hence, The velocity of the stone is 2.57 m/s.

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