Answer:
The batteries make it possible to store the electricity generated when the sun and wind peak so it can be available to the grid when electricity demand is at its peak.
Explanation:
Hope this helps!
If not, I am sorry.
The value of the acceleration is 0.76 m/s² and the total time taken by the vehicle is 39 seconds.
<h3>Acceleration of the vehicle</h3>
The acceleration of the vehicle before coming to rest is calculated as follows;
v² = u² + 2as
where;
- v is the final velocity
- u is the initial velocity
- a is the acceleration
- s is the distance traveled before stopping
the car came to rest with constant velocity attained after 12 seconds.
the initial velocity of the car before 12 seconds is zero.
v² = 0 + 2as
a = v²/2s
a = (10²)/(2 x 66)
a = 0.76 m/s²
<h3>Time of motion of the vehicle</h3>
d = ut + ¹/₂at²
where;
- d is the total distance traveled
- t is the time of motion
- a is acceleration
- u is initial velocity of the vehicle
580 = 0 + ¹/₂(0.76)t²
580 = 0.38t²
t² = 580/0.38
t² = 1,526.3
t = √1,526.3
t = 39 seconds
Thus, the value of the acceleration is 0.76 m/s² and the total time taken by the vehicle is 39 seconds.
Learn more about time of motion here: brainly.com/question/2364404
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Answer:
θ₁ = 3.35 10⁻⁴ rad
, θ₂ = 8.39 10⁻⁵ rad
Explanation:
This is a diffraction problem for a slit that is described by the expression
sin θ = m λ
the resolution is obtained from the angle between the central maximum and the first minimum corresponding to m = 1
sin θ = λ / a
as in these experiments the angle is very small we can approximate the sine to its angle
θ = λ / a
In this case, the circular openings are explicit, so the system must be solved in polar coordinates, which introduces a numerical constant.
θ = 1.22 λ / D
where D is the diameter of the opening
let's apply this expression to our case
indicates that the wavelength is λ = 550 nm = 550 10⁻⁹ m
the case of a lot of light D = 2 mm = 2 10⁻³ m
θ₁ = 1.22 550 10-9 / 2 10⁻³
θ₁ = 3.35 10⁻⁴ rad
For the low light case D = 8 mm = 8 10⁻³
θ₂ = 1.22 550 10-9 / 8 10⁻³
θ₂ = 8.39 10⁻⁵ rad
To calculate the horizontal distance traveled by the ball, we first calculate the total time it takes to reach the ground as follows:
t = √[2y/g] = <span>√[2(0.55) / 9.81]
t = 0.33 s
The horizontal distance would be
</span><span>X = Vx*t = 1.2*√[2*.55/9.8] = 0.4 m
</span>
Hope this helps.
Answer:
Could you please add the events
Explanation:
if not I could give a brief explanation of what happens in the phase and you could just eliminate?
