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4 years ago

Clare wants to mail a package that weighs 4 1/2 ponds what could be its volume in liters

Mathematics

1 answer:

Sati [7]4 years ago

7 0

Answer:

The volume in liters is 2.041165665 liter.

Step-by-step explanation:

Given : Clare wants to mail a package that weighs $4\frac{1}{2}$ pounds.

To find : What could be its volume in liters ?

Solution :

We know that,

Pound (lb) is a unit of Weight used in Standard system.

Liter (l) is a unit of Volume used in Metric system.

To convert 1 pound into liter is

1 pound (lb) = 0.45359237 liter (l)

$4\frac{1}{2}$ pounds in simpler fraction is $\frac{9}{2}$

Converting into liter,

$\frac{9}{2}$ pound (lb)= $\frac{9}{2}\times 0.45359237$ liter (l)

$\frac{9}{2}$ pound (lb) = 2.041165665 liter (l).

Therefore, the volume in liters is 2.041165665 liter.

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Factor completely. - 2x² + 20x – 48 = What is the missing factor?

Lemur [1.5K]

Answer:

- 2(x - 6)(x - 4)

Step-by-step explanation:

Given

- 2x² + 20x - 48 ← factor out - 2 from each term

= - 2 (x² - 10x + 24) ← factor the quadratic

Consider the factors of the constant term (+ 24) which sum to give the coefficient of the x- term (- 10)

The factors are - 6 and - 4, since

- 6 × - 4 = + 24 and - 6 - 4 = - 10, thus

x² - 10x + 24 = (x - 6)x - 4) and

- 2x² + 20x - 48 = - 2 (x - 6)(x - 4) ← in factored form

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Answer:

If you are solving for v, v= 27 cause 27+9=36 then you subtract 16 from 36 and it equals 20.

Step-by-step explanation:

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3 years ago

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My dad was painting our living room. He started with 5/9 of a can of paint.

SpyIntel [72]

Answer:

0.2 rounded up or 1/5 (also rounded up)

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3 years ago

Solve the elimination method

vlada-n [284]

Answer:

C)No Solution

Step-by-step explanation:

Given 2 equations

4x-2y=1
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Mentioned to solve using eliminations method

4x-2y=1

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Multiply second equation with 2

⇒second equation is 4x-2y=4

Now subtract second equation from 1st equation

4x-2y-(4x-2y)=1-4

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But 0≠3

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3 years ago

A psychology professor assigns letter grades on a test according to the following scheme. A: Top 7% of scores B: Scores below th

NISA [10]

Answer:

The minimum score required for an A grade is 89.8.

Step-by-step explanation:

We are given that a psychology professor assigns letter grades on a test according to the following scheme. A : Top 7% of scores. B : Scores below the top 7% and above the bottom 64%. C : Scores below the top 36% and above the bottom 25%. D : Scores below the top 75% and above the bottom 6%. F : Bottom 6% of scores.

Scores on the test are normally distributed with a mean of 78.4 and a standard deviation of 7.6.

Let X = Scores on the test

SO, X ~ Normal( $\mu=78.4,\sigma^{2} =7.6^{2}$ )

The z-score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean time = 78.4

$\sigma$ = standard deviation = 7.6

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, the minimum score required for an A grade so that it represents Top 7% of scores is given by;

P(X $\geq$ x) = 0.07 {where x is the required minimum score