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vichka [17]
3 years ago
12

Please help, I honestly have no clue if it's each or none.

Mathematics
1 answer:
RideAnS [48]3 years ago
6 0

Answer:

C there is no mode

Step-by-step explanation:

The mode is the number that appears most often.  Since there is no number that appears more than once, there is no mode

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How do i solve v=pi/3*r (squared)h for h
Colt1911 [192]
V=\dfrac{\pi}{3}\cdot r^2h\ \ \ \ \ |multiply\ both\ sides\ by\ 3\\\\\pi r^2h=3V\ \ \ \ |\divide\ both\ sides\ by\ \pi r^2\\\\\boxed{h=\dfrac{3V}{\pi r^2}}
3 0
3 years ago
Y= 7x - 19<br> y= 3x - 7<br><br> Solve for x and then use X to solve for y. (find x and y)
stepladder [879]

Answer:

(2,3)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the remainder when (3x4 + 2x3 − x2 + 2x − 24) ÷ (x + 2)?
ziro4ka [17]

Answer:

=38+x

Step-by-step explanation:

18-2+2x-24÷(x+2) =

16+2x-24-24÷(x+2)

24+16+2x

40+x+2

38+x

5 0
3 years ago
The tens digit is three less than the units digit. If the digits are reversed, the sum of the reversed number and the original n
muminat

Answer:

Original number is 47

Step-by-step explanation:

Given: The tens digit is three less than the units digit. If the digits are reversed, the sum of the reversed number and the original number is 121.

To find: the original number

Solution:

Let x denotes digit at ones place.

As the tens digit is three less than the units digit,

Digit at tens place = x-3

Original number = 10(x-3)+x=11x-30

When digits are reversed,

Reversed number = 10x+(x-3)=11x-3

As the sum of the reversed number and the original number is 121,

11x-30+11x-3=121\\22x-33=121\\22x=154\\x=\frac{154}{22}\\=7

So,

original number = 11x-30=11(7)-30=77-30=47

8 0
3 years ago
The time to complete the construction of a soapbox derby car is normally distributed with a mean of three hours and a standard d
TEA [102]

Answer:

The probability that it would take more than four hours to construct a soapbox derby car = 0.1587 or 15.87\%

Step-by-step explanation:

Given -

Mean (\nu )  = 3 hours

Standard deviation (\sigma  ) = 1 hours

Let X be the no of hours to construct a soapbox derby car

the probability that it would take more than four hours to construct a soapbox derby car =

P(X > 4)  = P(\frac{X - \nu }{\sigma}> \frac{4 - 3 }{1})

                = P(Z > 1)                   Put (Z = \frac{X - \nu }{\sigma})

                 =  1 -  P(Z <  1)            

                 =  1 - .8413                    Using z table

                  = 0.1587

3 0
3 years ago
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