Question

If 56.0 grams of nitrogen are used up by the reaction, how many grams of ammonia will be produced

Answer 1

Answer:

68 grams

Explanation:

Reaction that produces ammonia when nitrogen and hydrogen reacts is given by :-

$N_{2}$ + 3$H_{2}$ → 2N$H_{3}$

Clearly ,

When one mole of nitrogen reacts , two moles of ammonia will be produced.

Now,

weight of 1 mole of the Nitrogen = 28.0 grams

In 56.0 grams of the nitrogen , two moles will be present.

Thus , 4 moles of ammonia will be produced .

Weight of one mole of nitrogen = 17 grams.

Thus a total of 17× 4 = 68 grams f nitrogen will be produced.