Ask question

Ask question

All categories

Mekhanik [1.2K]

3 years ago

11

The acid-dissociation constant at 25.0 °c for hypochlorous acid (hclo) is 3.0 ⋅ 10−8. at equilibrium, the molarity of h3o+ in a

0.055 m solution of hclo is ________.

1 answer:

maks197457 [2]3 years ago

3 0

Hypochlorous acid is a weak acid. The $K_{a}$ value for the dissociation of HOCl is $3.0 * 10^{-8}$

You might be interested in

Describe three findings of the Human Genome Project<br> Write it in your own words

nata0808 [166]

Answer:

The biggest known human gene, is made up of about 2.4 million bases. The Human Genome Project also gave us more detailed information about chromosomes. It turns out that chromosome 1 contains the most genes, while the Y chromosome has the fewest.

Explanation:

3 0

3 years ago

PLSSS HEALP ASAP!!!! WILL REWARD

Liula [17]

A)1.75×3 moles of carbon monoxide

B)2:3

A)each mole of ferric oxide requires 3 moles of carbon monoxide. Therefore 1.75 moles requires 1.75 ×3 moles of carbon monoxide

6 0

2 years ago

Using the VSEPR theory , what would the representation mean A central atom with 2 connected atoms atom with I lone pair of Jone

VLD [36.1K]

Answer:

The molecule has a bent geometry

Explanation:

Let us look again at the principles of VSEPR theory. The shape of a molecule depends on the number of electron pairs that surround the valence shell of the central atom in the molecule.

Lone pairs distort the molecular geometry away from what is expected on the basis of VSEPR theory.

The molecule described in the question has the form AEX2. Two substituents and one lone pair form three electron domains around the central atom. The expected geometry is trigonal planar but the observed molecular geometry is bent because of the lone pairs present.

3 0

3 years ago

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

Read 2 more answers

Anyone can help me in science assignment

olya-2409 [2.1K]

Answer:

okay I will help you

Explanation:

okay

6 0

3 years ago

Read 2 more answers