Answer:
Y(OH)₃
Explanation:
Given ions:
Y³⁺ OH⁻
To find a neutral compound that conforms with the formation of the given ions;
We us the exchange of valency approach to solve this problem. The valency will form the combining power of the ions for the combination.
Y³⁺ OH⁻
Combining power 3 1
Exchange of valency 1 3
Now the compound is Y(OH)₃
Answer:
·
Explanation:
The final answer has a different set of units. In particular, millimoles (mmol) changes to moles (mol) and joules (J) changes to kilojoules (kJ). To make this change, you need to multiply the first value by proportions.
When writing these proportions, it is important that they are arranged in a way that allows for the cancellation of units. For instance, since J is located in the numerator, it must be located in the denominator of the conversion. Furthermore, since mmol is located in the denominator, it must be located in the numerator of the conversion.
<u>Proportions:</u>
1,000 J = 1 kJ
1,000 mmol = 1 mol
<u>The full expression:</u>
<h2>
·
·
=
^ ^</h2>
As you can see, the old units cancel out and you are left with kJ in the numerator and mol in the denominator.
Answer:
Explanation:
Hello there!
In this case, for these problem about the colligative property of freezing point depression, it is possible set up the following equation:
Whereas the van't Hoff's factor, i, is 2 since KCl is ionized in two ions (K+ and Cl-); and the molality (m) of the solution is computed by:
Thus, since the freezing point of water (ice) is 0°C, we obtain the following freezing point of the solution by plugging in:
Best regards!
Molar mass Na₂CO₃ = 106.0 g/mol
M(Na₂CO₃) = molarity x volume x molar mass
M(Na₂CO₃) = 0.250 x 2.00 x 106.0
M (Na₂CO₃) = 53 g
hope this helps!