Question

5) How many Kilograms are in 12 L of Chlorine Gas?

Answer 1

Answer: 0.03798 kilograms

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar Volume}}=\frac{12L}{22.4L}=0.535moles$

1 mole of chlorine gas $(Cl_2)$ weighs = 71 g

Thus 0.535 moles of chlorine gas $(Cl_2)$ will weigh = $\frac{71}{1}\times 0.535=37.98g=0.03798kg$            (1kg=1000g)

Thus there are 0.03798 kilograms in 12 L of chlorine gas.