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3 years ago

5) How many Kilograms are in 12 L of Chlorine Gas?

Chemistry

1 answer:

melamori03 [73]3 years ago

3 0

Answer: 0.03798 kilograms

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar Volume}}=\frac{12L}{22.4L}=0.535moles$

1 mole of chlorine gas $(Cl_2)$ weighs = 71 g

Thus 0.535 moles of chlorine gas $(Cl_2)$ will weigh = $\frac{71}{1}\times 0.535=37.98g=0.03798kg$ (1kg=1000g)

Thus there are 0.03798 kilograms in 12 L of chlorine gas.

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35.0 mL of acid with an unknown concentration is titrated with 24.6 mL of 0.432 M base. What is the concentration of the acid? A

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I’LL MAKE YOU BRAINLIEST+ FREE POINTS

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Answer:

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Explanation:

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In summary, a dilution is a lower concentration solution than the original.

The way to do the calculations in a dilution is through the expression:

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In this case, being:

Ci= 7 M
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Replacing:

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