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zlopas [31]
2 years ago
15

A 32.8 g iron rod, initially at 22.4 C, is submerged into an unknown mass of water at 63.1 C, in an insulated container. The fin

al temperature of the mixture upon reaching thermal equilibrium is 59.1 C.What is the mass of the water?
Chemistry
1 answer:
laila [671]2 years ago
3 0

Answer:

mass water = 32.4 g

Explanation:

specific heat iron = 0.450 J/g°C

specific heat water = 4.18 J/g°C

32.8 x 0.450 ( 59.1 - 22.4) + mass water x 4.18 ( 59.1- 63.1)=0

541.7 - mass water x 16.7 = 0

mass water = 32.4 g

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Answer:

The new pressure is 44.4 kPa.

Explanation:

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PV=k\\\\P_1V_1=P_2V_2

P_2 is final pressure

P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{22\times 101\times 10^3}{50}\\\\P_2=44440\ Pa\\\\P_2=44.4\ kPa

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What is the name of the compound CO?
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PLEASE HELP!! A gas has a volume of 7.9 L at a temperature of 222. K and pressure of 877 mmHg. What is the new temperature (in C
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82.97 K

Explanation:

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PV/T = P'V'/T'................ Equation 1

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Hence the new temperature is 82.97 K

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