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Monica [59]
3 years ago
8

Astronomers have not yet reported any Earth-like planets orbiting other stars because (a) there are none; (b) they are not detec

table with current technology; (c) no nearby stars are of the type expected to have Earth-like planets; (d) the government is preventing us from reporting their discovery.
Physics
1 answer:
Zigmanuir [339]3 years ago
3 0

Answer:

(b) they are not detectable with current technology

Explanation:

The improvement in exoplanet detection methods in recent years, thanks to spaces telescopes such as the Kepler, has led to a revolution in the field of astronomy. The findings have gone from focusing on Jupiters hot to super-earth and, ultimately, to Earth-like planets.

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A 25-ohm resistor at steady state draws a current of 10.8 amperes. its temperature is 310 k; the temperature of the surroundings
MA_775_DIABLO [31]

The total rate of entropy generation is 0.268 J/K.

Entropy, the degree of a gadget's thermal electricity consistent with unit temperature that is unavailable for doing useful paintings. due to the fact work is acquired from ordered molecular motion, the quantity of entropy is likewise a measure of the molecular sickness, or randomness, of a machine.

Resistance of resistor R = 25 ohm

the total rate of entropy generation ?

Current flowing through resistor I = 10 A

Heat generation due to resistance , Q = I2R = 100*25 = 2500 J

Resistor temperature T = 310 K

Surrounding temperature Ts = 300 K

Entropy change for Resistor, heat lost due to the resistance to the surrounding then Q = -ve

(ΔS)syst = - Q/T = - 2500 J/310K = - 8.064 J/K

Entropy change for the system: here heat gain from the resistor, Q = +ve

(ΔS)surr = +Q/Ts = 2500J/300K = 8.333 J/K

Total Entropy generation :

(ΔS)tot = (ΔS)syst + (ΔS) Surr = -8.064 + 8.333 = 0.268 J/K

Learn more about entropy here:- brainly.com/question/6364271

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3 0
2 years ago
A 3.00 m-long 6.00-kg ladder pivoted at the top hangs down from a platform at the circus. A 42.0-kg trapeze artist climbs to a p
statuscvo [17]

Answer:

The period of the system of ladder and woman, T = 2.5 seconds

Explanation:

Mass of the ladder, m_1 = 6 kg

Mass of the artiste, m_2 = 42.0 kg

Length of the ladder, L = 42.0 kg

The total moment of inertia can be calculated using the equation:

I = \frac{1}{3} M_1 L^2 + m_2 (\frac{L}{2} )^2\\I = \frac{1}{3} *6*3^2 + 42* (\frac{3}{2} )^2\\I = 18 + 94.5\\I = 112.5 kg m^2

D = L/2 = 3/2

D = 1.5 m

The frequency of the system of ladder and woman follows that of a physical pendulum which can be given by the equation:

f = \frac{1}{2\pi } \sqrt{\frac{mgD}{I} } \\f = \frac{1}{2\pi } \sqrt{\frac{48*9.8*1.5}{112.5} }\\f = 0.4

The period of the system of ladder and woman is given by:

T = 1/f

T = 1/0.4

T = 2.5 seconds

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3 years ago
HELP! NEED THE ANSWER IN 6 MINS!!!!!!!!!!!!!!!
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Answer:

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