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hodyreva [135]
3 years ago
11

A 2.0 cm thick brass plate (k_r = 105 W/K-m) is sealed to a glass sheet (kg = 0.80 W/K m), and both have the same area. The expo

sed face of the brass plate is at 80°C, while the exposed face of the glass is at 20 °C. How thick is the glass if the glass brass interface is at 65 C? Ans. 0.46 mm​
Physics
1 answer:
astraxan [27]3 years ago
6 0
I need a good phisics teacher for one day online please123
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The largest possible displacement you can get by combining the two of them is if they're both in the SAME direction. You walk 3 meters, stop for a breath, then walk another 4 meters in the same direction as the first one. The resultant is 7 meters.

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A playground merry-go-round of radius r = 2.00 m has a moment of inertia = 250 ⋅ , and is rotating at 10.0 rev/min about a frict
bagirrra123 [75]

Answer:

330kgm^2

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3 years ago
Party hearing. As the number of people at a party increases, you must raise your voice for a listener to hear you against the ba
dusya [7]

Answer:

\frac{r_i}{1.77} m

Explanation:

Given that

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And the increase in background noise by Δβ = 5 dB, due to which the level of sound also rises

Based on the above information, the separation rf that is needed is shown below:

As we know that

I_f = I_o \times 10^{\frac{\beta}{10} }\\\\I_f = I_i \times 10^{0.5}\\\\I_f = 3.16 \times  I_i\\\\I \alpha \frac{1}{r^2} \\\\\frac{r_i^2}{r_f^2} = 3.16\\\\r_f = \frac{\sqrt{r_i^2}}{{\sqrt3.16}} \\\\= \frac{r_i}{1.77} m

Hence, the separation r_f i.e. required is  \frac{r_i}{1.77} m

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