The average rate of change (AROC) of a function f(x) on an interval [a, b] is equal to the slope of the secant line to the graph of f(x) that passes through (a, f(a)) and (b, f(b)), a.k.a. the difference quotient given by
![f_{\mathrm{AROC}[a,b]} = \dfrac{f(b)-f(a)}{b-a}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5Ba%2Cb%5D%7D%20%3D%20%5Cdfrac%7Bf%28b%29-f%28a%29%7D%7Bb-a%7D)
So for f(x) = x² on [1, 5], the AROC of f is
![f_{\mathrm{AROC}[1,5]} = \dfrac{5^2-1^2}{5-1} = \dfrac{24}4 = \boxed{6}](https://tex.z-dn.net/?f=f_%7B%5Cmathrm%7BAROC%7D%5B1%2C5%5D%7D%20%3D%20%5Cdfrac%7B5%5E2-1%5E2%7D%7B5-1%7D%20%3D%20%5Cdfrac%7B24%7D4%20%3D%20%5Cboxed%7B6%7D)
Answer:
i got 2808 in3 which wasn't on the list and i was extremely confused, i redid the problem multiple times and got the same answer, i used a calculator AND searched of the web, it still gave me the same answer, if those are the only options something might be wrong, the answer should be 2808 in3.
You need to solve this for h(t)=0
<span>-16t^2-30t+124=0
This has two solutions, one is negative that does not make sense as time cannot be negative.
The positive solution is t=2
So the interval where it is in the air is [0;2)
</span>
Answer:
Step-by-step explanation:
Given
Joaquin's score is 
and Trisha's score is 
Arranging score in order of value we get
Joaquin's : 
Trisha's : 
as no of values is even therefore their median is
Joaquin's
Trisha's 
Therefore median of Joaquin's is lower
Thus Joaquin wins the game
Answer:
3/8, 2/5, 11/20, 23/40, 7/10, 3/4
Step-by-step explanation:
Just change them all to the same denominator and you're good. Put all of the fractions' denominators to 40 as that's the least common denominator. 3/4 turns into 30/40. 2/5 turns into 16/40. 3/8 turns into 15/40. 7/10 turns into 28/40. 11/20 turns into 22/40. And 23/40 stays as it is, because the denominator is already 40.
Putting them in order is now simple,
3/8 (15/40) < 2/5 (16/40) < 11/20 (22/40) < 23/40 < 7/10 (28/40) < 3/4 (30/40)
***When you multiply any fraction to change its denominator, multiply it by the same thing to the numerator as well.
Good Luck!
