Multiply 9.0g/cm3 by 0.31g = 2.79cm3
In NH4OH, the compounds that make it up are NH4+ and OH-
Therefore N exists in the ammonium form.
In the ammonium ion 4H atoms are connected to N.
N is more electronegative than H, therefore when H bonds to N, H is the more positive atom therefore each H has a charge of +1, since there are 4 H atoms the charge contributed by the 4H atoms are +1 * 4 = +4
the overall charge of NH4 is +1
Charge of N (+) +4 = +1
Charge of N = +1 - 4
Therefore oxidation state of N in NH4 is = -3
Answer: -
4.25 mol of O₂ left as excess.
3.5 mol of NO₂ formed.
Explanation: -
Number of moles of NO taken = 3.5
Number of moles of O₂ taken = 6.0
The balanced chemical equation for this reaction is
2 NO+ O₂ → 2 NO₂
From the equation we can see that
2 mol of NO react with 1 mol of O₂
3.5 mol of NO react with
x 3.5 mol NO
= 1.75 mol O₂
So Oxygen O₂ is in excess and NO is the limiting reagent.
Moles of O₂ left over = 6 - 1.75 =4.25 mol of O₂
From the balanced chemical equation we see
2 mol of NO gives 2 mol of NO₂
3.5 mol of NO gives
x 3.5 mol NO
= 3.5 mol of NO₂
Answer:
Correct option : "The mechanism results in a carbocation rearrangement in which a methyl shift occurs"
Explanation:
In the first step, 2,2-dimethyl-1-propanol gets protonated.
In the second step, a carbocationic intermediate is produced from removal of
.
In the third step, shifting of methyl group occurs to produce more stable carbocationic intermediate.
In the fourth step,
attacks the stable carbocation to produce 2-bromo-2-methylbutane.
So, correct option : "The mechanism results in a carbocation rearrangement in which a methyl shift occurs"
Full reaction mechanism has been shown below.
The solid metal inner core is the most dense