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Vladimir79 [104]
3 years ago
12

Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?

Chemistry
2 answers:
oksian1 [2.3K]3 years ago
8 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

When carbon burns in the presence of oxygen, it produces a gas named as carbon dioxide.

To write a chemical equation, we must follow some of the rules:

  • The reactants are always written on the left side of the direction arrow.
  • A '+' sign is written between the reactants, if more than one reactants are present.
  • An arrow is added after all the reactants are written.
  • The arrow tells us where the reaction is proceeding.
  • The products are written on the right side of the direction arrow.
  • A '+' sign is written between the products, if more than one reactant is present.

Here, carbon and oxygen are the reactants and carbon dioxide is the product.

Thus, the chemical equation representing this reaction follows:

\text{Carbon}+\text{Oxygen}\rightarrow \text{Carbon dioxide}

Hence, the correct answer is Option B.

Alex73 [517]3 years ago
3 0
Your answer is B.
Because it says that that carbon burns in presence of oxygen (C+O) which is equal ( => ) to Carbon Dioxide (CO_{2})
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Now we will reverse the reaction 3, multiply reaction 2 by 2  then adding all the equations, Using Hess's law:

We get :

C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole..[1]

2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol..[2]

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\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3

\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)

\Delta H=-238.7kJ/mole

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