Answer:
total surface area of cone is πr (r+l)
22/7 x 3 (3+4)
22/7*3 (7)
22 x 3 ( as 7 that was divided by 22 was cut out with 7 in the bracket)
hence,
TSA of cone = 66pi
Answer:
1. (2x^2+x-1)
Step-by-step explanation:
expanding (2x^2-1)^2. multiplying (x-2) (1-2x)
= 4x^2-4x+1. = x-2x^2-2+4x
= -2x^2+5x-2
(4x^2-4x+1-2x^2+5x-2)
=2x^2+x-1
Answer:
The density of the bar of gold is 19.32 grams per cubic centimeter .
Step-by-step explanation:
Formula
As given
A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.
As 1 kilogram = 1000 gram
Than convert 13.949 kilograms into grams.
13.949 kilograms = 13.949 × 1000 grams
= 13949 grams
Mass = 13949 grams
Volume = 722 cubic centimeter
As put in the formula
Density = 19.32 grams per cubic centimeter (Approx)
Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .
Answer:
Step-by-step explanation:
• AB, BC, and AC form a triangle. Enter a possible value of AC....
So it asks for only a possible value of AC as there are many possible values.
Given AB = 8 cm and BC = 6 cm, they are in the ratio of 3:4.
Line segments of 3, 4 and 5 length will form a right-angled triange.
A possible value of AC = 5*2 = 10cm
• Points A, B, and C lie on the same line, and C lies between A and B.
So AC+CB = AB
AC+6 = 8
AC = 2cm
Enter this value of AC in the second
response box.
Answer:yes
Step-by-step explanation:
