Explanation:
The given reaction will be as follows.

Hence, expression that represents relation between given reaction and Q will be as follows.
Q = ![\frac{[Br^{-}]^{2}[SO^{2-}_{4}][H^{+}]^{4}}{[Br_{2}]P_{SO_{4}}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BBr%5E%7B-%7D%5D%5E%7B2%7D%5BSO%5E%7B2-%7D_%7B4%7D%5D%5BH%5E%7B%2B%7D%5D%5E%7B4%7D%7D%7B%5BBr_%7B2%7D%5DP_%7BSO_%7B4%7D%7D%7D)
= ![\frac{(11.85)^{2} \times (8.35) \times [H^{+}]^{4}}{(2.5 \times 10^{4}) \times 2.50 \times 10^{5}}](https://tex.z-dn.net/?f=%5Cfrac%7B%2811.85%29%5E%7B2%7D%20%5Ctimes%20%288.35%29%20%5Ctimes%20%5BH%5E%7B%2B%7D%5D%5E%7B4%7D%7D%7B%282.5%20%5Ctimes%2010%5E%7B4%7D%29%20%5Ctimes%202.50%20%5Ctimes%2010%5E%7B5%7D%7D)
![[H^{+}]^{4} = 7.46 \times 10^{-34}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%5E%7B4%7D%20%3D%207.46%20%5Ctimes%2010%5E%7B-34%7D)
As relation between pH and
is as follows.
pH = -log ![[H^{+}]](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D)
= -log 
= -(0.717 - 10)
= 9.28
Thus, we can conclude that the pH needed to produce the given value of Q is 9.28.
Answer:
113 kJ or 113,000J
Explanation:
Since we are condensing it, a physical change in the state of matter is occurring. 113 kJ or 113,000J because of the following equation: Q = 2260 times 50. 2260 is the Heat of Vaporization constant.
Answer:
1 atm
Explanation:
The normal boiling point of a liquid is temperature at which the vapour pressure of the liquid equals 1 atm.
If the normal boiling point of cyclohexane is 81.0 °C, the vapour pressure of the liquid is 1 atm.
The graph below shows that the vapour pressure of cyclohexane reaches 1 atm at about 81 °C.
In petroleum geology, a trap is a geological structure affecting the reservoir rock and caprock of a petroleum system allowing the accumulation of hydrocarbons in a reservoir. Traps can be of two types: stratigraphic or structural.
Answer:
Number of iodine atoms = 2 × 4 = 8
Number of oxygen atoms = 2 × 9 = 18
Explanation:
Coefficient 2 is placed in front of the product tetraiodine nonaoxide:
= 
Number of iodine atom in a single molecule tetraiodine nonaoxide = 4
Number of oxygen atoms in a single molecule tetraiodine nonaoxide = 9
Coefficient 2 is placed in front of the product tetraiodine nonaoxide:
= 
Number of iodine atoms = 2 × 4 = 8
Number of oxygen atoms = 2 × 9 = 18