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Karolina [17]
3 years ago
14

PLS HELP ME WITH THESE TWO QUESTIONS WILL MARK U AS BRAINLIEST !!

Chemistry
1 answer:
Degger [83]3 years ago
4 0

Answer:

See explanation

Explanation:

From the parameters provided;

V=?

n= 1.46 moles

P= 0.982 ATM

T= 13°C + 273 = 286 K

R = 0.0821 L.atm/mol.K

From

PV= nRT

V= nRT/P

V= 1.46 × 0.0821 × 286/0.982

V= 34.9 L

b) Boyle's law states that, the pressure of a given mass of gas is inversely proportional to its volume at constant temperature and pressure. This statement is a correct postulation about ideal gases which can be arrived at from the kinetic theory of gases.

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Calculate the energy required to heat 322.0g of ethanol from −2.2°C to 19.6°C . Assume the specific heat capacity of ethanol und
just olya [345]

Answer:

There is 17.1 kJ energy required

Explanation:

Step 1: Data given

Mass of ethanol = 322.0 grams

Initial temperature = -2.2 °C = 273.15 -2.2 = 270.95K

Final temperature = 19.6 °C = 273.15 + 19.6 = 292.75 K

Specific heat capacity = 2.44 J/g*K

Step 2: Calculate energy

Q = m*c*ΔT

⇒ m = the mass of ethanol= 322 grams

⇒ c = the specific heat capacity of ethanol = 2.44 J/g*K

⇒ ΔT = T2 - T1 = 292.75 - 270.95 = 21.8 K

Q = 322 * 2.44 * 21.8 = 17127.8 J = 17.1 kJ

There is 17.1 kJ energy required

3 0
3 years ago
Question 10 (1 point)
levacccp [35]
The empirical formula gives the relative ratio of atoms in each element. Therefore, it simplifies the whole numbers. For example C2H6 can be reduced to CH3 because they share the greatest common factor (2). The answer to this question would be #1. C4H10 can be reduced to C2H5 because 4 and 10 are both divisible by 2. C2H5 can not be reduced any further. All of the other options do not have a greatest common factor making them a empirical formula.
4 0
3 years ago
How much heat must be absorbed by 125 g of ethanol to change its temperature from 21.5 ∘C to 34.8 ∘C? (Specific heat capacity of
Katarina [22]

Answer:

Option D. 4.02 kJ

Explanation:

A simple calorimetry problem

Q = m . C . ΔT

ΔT = Final T° - Initial T°

C = Specific heat capacity

m = mass

Let's replace the data

Q = 125 g . 2.42 J/g∘C . (34.8°C -21.5 °C)

Q= 4023.25 J

We must convert the answer to kJ

4023.25 J . 1kJ /1000 =4.02kJ

3 0
3 years ago
I’m not sure quite sure about this one please help
ehidna [41]
This one is correct
3 0
3 years ago
1. Calculate the energy of a photon with a frequency of 3x1015 Hz.<br> ?????
Afina-wow [57]

Answer:

1.99 x 10⁻¹⁸J

Explanation:

Given parameters:

Frequency of the wave  = 3 x 10¹⁵Hz

Unknown:

Energy of the photon  = ?

Solution:

To solve this problem, we use the expression below;

     E  = hf

Where E is the energy, h is the Planck's constant and f is the frequency

Now insert the parameters and solve for E;

     E  = 6.63 x 10⁻³⁴ x 3 x 10¹⁵ = 19.9 x 10⁻¹⁹J or 1.99 x 10⁻¹⁸J

6 0
3 years ago
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