Explanation:
Different atoms binds their outermost shell electrons with different amount of energy.
The amount of energy required to remove an electron from an atom is the ionization energy.
- Ionization energy measures the readiness of an atom to lose electrons.
- From the given problem, we can infer that in group O the ionization energy decreases down the group.
- Helium has the highest ionization energy.
- Down a group on the periodic table, ionization energy decrease because:
- atomic radii increases down the group.
- there is an increasing shielding/screening effect of inner shell electrons on the outermost shell electrons.
Learn more:
Ionization energy brainly.com/question/2153804
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The answer would be C) Observe and ask questions because if we do process of elimination we see that drawing conclusions is NOT the first step, forming a hypothesis and illustrating the process is part of the method, but NOT the first step.
1 Cal ---------- 4.184 J
? Cal ---------- 130.0 J
130.0 x 1 / 4.184 => 31.07 Cal
hope this helps!
Answer:
2 Cr(s) + 3 Fe(NO3)2(aq) = 3 Fe(s) + 2 Cr(NO3)3(aq)
Explanation:
I balanced this chemical equation so that both sides are equal, meaning that the mass of reactants is equal to mass of products.
