All categories

2 years ago

PLS HELP ME WITH THESE TWO QUESTIONS WILL MARK U AS BRAINLIEST !!

Chemistry

1 answer:

Degger [83]2 years ago

4 0

Answer:

See explanation

Explanation:

From the parameters provided;

V=?

n= 1.46 moles

P= 0.982 ATM

T= 13°C + 273 = 286 K

R = 0.0821 L.atm/mol.K

From

PV= nRT

V= nRT/P

V= 1.46 × 0.0821 × 286/0.982

V= 34.9 L

b) Boyle's law states that, the pressure of a given mass of gas is inversely proportional to its volume at constant temperature and pressure. This statement is a correct postulation about ideal gases which can be arrived at from the kinetic theory of gases.

You might be interested in

Do bases react with metals the same way that acids do?.

mina [271]

Answer:

Bases do not react with metals in the way that acids do

Explanation:

hope this helps

pls mark brainliest

6 0

1 year ago

A light bulb has resistance 12 12 when the

Mkey [24]

Explanation:

Given :

V=6V

R=12 ohm

I=?

I=V/R

=6/12

=0.5 A

8 0

2 years ago

Type of introduction

AlladinOne [14]

Answer:

Five Types of Introductions.

“Inquisitive” Explain why your subject is important, curious, or interesting.

“Paradoxical” Explain what aspects of your subject seem improbable. ...

“Corrective” Explain how your subject has been misunderstood or misrepresented by others. ...

8 0

3 years ago

Calculate the volume, in milliliters, for the following:

fredd [130]

Answer: The volume for 0.850 mol of $NaNO_{3}$ from a $NaNO_{3}$ solution is 1700 mL.

The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

Explanation:

Molarity is the number of moles of solute present in a liter of solution.

As given moles of $NaNO_{3}$ are 0.850 mol and molarity of $NaNO_{3}$ solution is 0.5 M. Hence, its volume is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\0.5 M = \frac{0.850 mol}{Volume}\\Volume = 1.7 L (1 L = 1000 mL)\\= 1700 mL$

Therefore, the volume for 0.850 mol of $NaNO_{3}$ from a $NaNO_{3}$ solution is 1700 mL.

As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{30.0 g}{23.95 g/mol}\\= 1.25 mol$

So, volume for LiOH solution is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\2.70 M = \frac{1.25}{Volume}\\Volume = 0.464 L (1 L = 1000 mL)\\= 464 mL$

Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

6 0

2 years ago

Calculate the average atomic mass of sulfur if 95.00% of all sulfur atoms have a mass of 31.972 amu, 0.76% has a mass of 32.971

Nadusha1986 [10]

Answer:

32.057 amu

Explanation:

$\text{Average atomic mass = Mass}\times \text{abundances}$

$M=95\%\ \text{of}\ 31.972 +0.76\%\ \text{of}\ 32.971 +4.22\%\ \text{of}\ 33.967 \\\\M=\dfrac{95}{100}\times 31.972 +\dfrac{0.76}{100}\ \times \ 32.971 +\dfrac{4.22}{100} \times \ 33.967\\\\M=32.057\ \text{amu}$

So, the average atomic mass of sulfur is 32.057 amu.

7 0

3 years ago