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ale4655 [162]
3 years ago
15

A block of iron has a mass of 150 g and a volume of 20 ml. What is the density of iron? *

Chemistry
2 answers:
Fiesta28 [93]3 years ago
7 0
M/V=d
150/20=7.5
Density= 7.5
shtirl [24]3 years ago
4 0

Answer:

<h3>The answer is 7.50 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass of iron = 150 g

volume = 20 mL

We have

density =  \frac{150}{20}  =  \frac{15}{2}  \\

We have the final answer as

<h3>7.50 g/mL</h3>

Hope this helps you

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Q #4 please help if you are sure
Mashutka [201]

(Answer) (d) Chemical reaction rates vary with the conditions of the reaction, but nuclear decay rates do not.

Rate of a chemical reaction refers to rate of formation of products from reactions during a chemical reaction. The rates of chemical reactions depend on various factors such as temperature, pressure, concentration of reactants, presence of catalyst etc. For this reason, chemical reaction rates vary with the conditions of the reaction.

Nuclear decay rate refers to the constant ratio of the number of atoms of radioactive nucleus that decay during a certain interval of time to the total number of radioactive atoms at the beginning of the time interval. Nuclear decay rates are constant and do not vary with the conditions of the reaction.

8 0
3 years ago
Determine the [OH-], pH, and pOH of a solution with a [H+] of 0.090 M at 25 °C. [OH-] = pH = pOH = 0 POH =
ValentinkaMS [17]

Answer : The concentration of OH^- ion, pH and pOH of solution is, 1.12\times 10^{-13}M, 1.05 and 12.95 respectively.

Explanation : Given,

Concentration of H^+ ion = 0.090 M

pH : It is defined as the negative logarithm of hydrogen ion or hydronium ion concentration.

The expression used for pH is:

pH=-\log [H^+]

First we have to calculate the pH.

pH=-\log [H^+]

pH=-\log (0.090)

pH=1.05

The pH of the solution is, 1.05

Now we have to calculate the pOH.

pH+pOH=14\\\\pOH=14-pH\\\\pOH=14-1.05=12.95

The pOH of the solution is, 12.95

Now we have to calculate the OH^- concentration.

pOH=-\log [OH^-]

12.95=-\log [OH^-]

[OH^-]=1.12\times 10^{-13}M

The OH^- concentration is, 1.12\times 10^{-13}M

5 0
3 years ago
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Answer:Naoh and animal fats

Explanation:

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Feel pleasure to help u

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3 years ago
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Oduvanchick [21]
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alukav5142 [94]

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Internally reversible is the answer.

Explanation:

3 0
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