Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
The equation used in this problem is <span>f(x)=x^4−x^3−2x−4
The factored version is F(x)=(x-2)(x+1)((x^2)+2)
-I hope this is the answer you are looking for, feel free to post your questions here on brainly in the future.</span>
The answer is 100 square inches
Answer:
Y = 1/2
Step-by-step explanation:
6/36 = y/3
Y = 1/2
Just multiply 3 by both sides
