1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tamiku [17]
4 years ago
9

What is the product? (2x – 1)(x 4)?

Mathematics
2 answers:
Vedmedyk [2.9K]4 years ago
7 0

Answer:

2x^2+7x-4

Step-by-step explanation:

The distributive says that:

a \cdot(b+c) = a\cdot b+ a\cdot c

To find the product of :

(2x-1)(x+4)

then;

2x(x+4)-1(x+4)

Using distributive property we have;

2x^2+8x-x-4

Combine like terms;

2x^2+7x-4

Therefore, the product of (2x-1)(x+4) is, 2x^2+7x-4

kupik [55]4 years ago
4 0
Not sure if it is correct, but:

2x2 (2x on level 2) - 7x + 4
You might be interested in
Javier is saving for a new pair of shoes that costs $59.99. So far, he has saved $22.50. How much more does he need to save? Sho
Neko [114]

Answer:

hi there user!

The answer is he needs to save $37.49 more

Step-by-step explanation:

59.99 - 22.50 = 37.49

8 0
3 years ago
Find the radius of the circle whose equation is 3x² + 3y² = 75.
Flauer [41]

Answer:

<h2>A) 5</h2>

Step-by-step explanation:

The equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the equation:

3x^2+3y^2=75             <em>divide both sides by 3</em>

x^2+y^2=25\to r^2=25\to r=\sqrt{25}\to r=5

7 0
4 years ago
I NEED HELP ON THESE QUESTIONS QUICKLY PLEASE!!!!
Korvikt [17]

The objective function Z = 2x + 3y cannot be maximized, while the maximum value of the objective function Z = 2x + 5y is 19

<h3>Part A (Question 1): Maximize Z</h3>

The objective function is given as:

Z = 2x + 3y

The constraints are given as:

3x+2y≤15

4x+y≤0

x≥0; y≥0

See attachment for the graph of the constraints

From the attached graph, we have the optimal solution to be:

(x,y) = (-3,12)

Because x≥0 & y≥0, and x is negative in (-3,12), then

The function cannot be maximized.

<h3>Part B (Question 7): Maximize Z</h3>

The objective function is given as:

Z = 2x + 5y

The constraints are given as:

x + y ≤ 5

y - x ≤ 1

x≥0; y≥0

See attachment for the graph of the constraints

From the attached graph, we have the optimal solution to be:

(x,y) = (2,3)

Substitute 2 and 3 for x and y in the objective function.

Z = 2 * 2 + 5 * 3

Evaluate

Z = 19

Hence, the maximum value of the objective function is 19

The questions 21, 22, 23 and 25 are not included in the attachment

Read more about maximized functions at:

brainly.com/question/16826001

#SPJ1

8 0
2 years ago
Grandma has 4 bags of soil for her flower pots each flower pot needs 3/4 of a bag of soil how many flower pots can she fill
Ostrovityanka [42]

Answer:

she can fill 5 pots and have 1/3 bag left over

Step-by-step explanation:

4 0
3 years ago
Need help plzzzz 5(a+b)-a-b
finlep [7]
Distribute the 5 into the polynomial to get 5a + 5b - a - b. Combine like terms to get 4a + 4b, your answer. 
5 0
4 years ago
Other questions:
  • The NewLargeLand is a large breed of a dog. It weighs about 10 x 10 pounds. Write 10 x 10 using an exponent. Then find the value
    13·1 answer
  • Determinati numerele natrale x care sunt soltii ale incuatiilor:
    12·1 answer
  • Can someone help with this math question please
    12·1 answer
  • Write each expression using a single exponent.
    9·1 answer
  • Bagels: six in a bag Apples: eight in a bag Cookies: twelve in a box Juice Boxes: nine in a box Find the least number of package
    10·1 answer
  • If you're good at trig please help meeeeeee<br> Show full working out thank you ;)
    11·1 answer
  • Points points points
    6·2 answers
  • It is estimated that the population of the world is increasing at an average rate of 1.09%. The population was about 7,632,819,3
    5·1 answer
  • I don't understand math @ all please help
    15·1 answer
  • I need help asap pleaseeee
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!