<h2>Hello!</h2>
The answer is:
C. Cosine is negative in Quadrant III
<h2>
Why?</h2>
Let's discard each given option in order to find the correct:
A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).
B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.
C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.
D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)
Have a nice day!
Answer:
The solution is obtained by adding the two equations.
The solution is: (x, y) = (
, 
)
Step-by-step explanation:
We are given two equations with two variables. The strategy is to eliminate one variable and solve for both the variables.
The two equations are:
Adding both the equations, we get:
Substituting the value of 'x', we get the value of y.
We substitute in (2). [Can be substituted in any equation].
We get: y = 2x - 1
So, we get the corresponding values of x and y which is the solution of the two equations.
Answer:
Step-by-step explanation:
sin 45 = opposite / hypotenuse
<u>Where opposite = x , hypotenuse = 4</u>
sin 45 = x / 4
![\sf \frac{\sqrt{2} }{2 } = \frac{x}{4} \\\\x = \frac{4\sqrt{2} }{2} \\\\x = 2\sqrt{2} \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Csf%20%5Cfrac%7B%5Csqrt%7B2%7D%20%7D%7B2%20%7D%20%3D%20%5Cfrac%7Bx%7D%7B4%7D%20%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B4%5Csqrt%7B2%7D%20%7D%7B2%7D%20%5C%5C%5C%5Cx%20%3D%202%5Csqrt%7B2%7D%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
y = 3x
Step-by-step explanation:
Slope equation:
y2 - y1
--------
x2 - x1
----------------------------------------------------------------------------------------------------------------
6 - 0 6
m = ----------- = ----- = 3
2 - 0 2
Your slope is 3.
----------------------------------------------------------------------------------------------------------------
Equation:
y = mx + b
Plug in the slope and you get:
y = 3x + b
----------------------------------------------------------------------------------------------------------------
Now to find b, you can use either coordinate point. So I will show you both ways :)
<u>(0,0)</u> <u>(2,6)</u>
0 = 3(0) + b 6 = 3(2) + b
Multiply 0 and 3 Multiply 2 and 3
0 = 0 + b 6 = 6 + b
Subtract 0 to 0 Subtract 6 from 6
0 = b 0 = b
There is no y-intercept
----------------------------------------------------------------------------------------------------------------
Your answer: y = 3x
Hope this helped :)
The first one simplified is 2j-2k
30% of 520 is 156
