The number of mole of ammonium ion, NH₄⁺ in the solution is 0.175 mole
We'll begin by calculating the number of mole of NH₄NO₃ in the solution. This can be obtained as follow:
Volume = 125 mL = 125 / 1000 = 0.125 L
Molarity = 1.40 M
<h3>Mole of NH₄NO₃ =? </h3>
Mole = Molarity x Volume
Mole of NH₄NO₃ = 1.40 × 0.125
<h3>Mole of NH₄NO₃ = 0.175 mole</h3>
Finally, we shall determine the number of mole of ammonium ion, NH₄⁺ in the solution. This can be obtained as follow:
NH₄NO₃(aq) —> NH₄⁺(aq) + NO₃¯(aq)
From the balanced equation above,
1 mole of NH₄NO₃ contains 1 mole of NH₄⁺
Therefore,
0.175 mole of NH₄NO₃ will also contain 0.175 mole of NH₄⁺
Thus, the number of mole of ammonium ion, NH₄⁺ in the solution is 0.175 mole
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