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Ber [7]
3 years ago
6

What does coal produce during its combustion?​

Chemistry
1 answer:
natali 33 [55]3 years ago
4 0

Answer:

sulphur dioxide, nitrogen oxides, carbon dioxide, volatile organic compounds, ash and a range of heavy metals

Explanation:

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Use the periodic table to complete each nuclear fusion equation.
Verdich [7]

Answer: A:5 B:2 C:15 D:8 E:O

Explanation:

just checked on edg

6 0
4 years ago
Read 2 more answers
How many copper atoms are in 70g of copper
Elanso [62]

Answer:

n = 6.634\times 10^{23}\,atoms

Explanation:

The total amount of atoms is found by multiplying Avogradro's Number and the number of moles:

n = \left(6.022\times 10^{23}\,\frac{atoms}{mol} \right)\cdot \left(\frac{70\,g}{63.546\,\frac{g}{mol} } \right)

n = 6.634\times 10^{23}\,atoms

4 0
3 years ago
What gives the gem amethyst its purplish color?
Alina [70]
iron Presence of trace elements, irradiation and iron impurities give the gem amethyst its purplish color!
7 0
3 years ago
2CH2(g) + 50 (g) → 400/(g) + 2 H2O(g)
Nadusha1986 [10]

168.96 g of carbon dioxide (CO₂)

Explanation:

The chemical reaction representing the combustion of acetylene:

2 C₂H₂ (g) + 5 O₂ (g)→ 4 CO₂ (g) + 2 H₂O (g)

number of moles = mass / molecular weight

number of moles of acetylene (C₂H₂) = 50 / 26 = 1.92 moles

Taking in account the stoichiometry of the chemical reaction, we devise the following reasoning:

if       2 moles of acetylene (C₂H₂) produces 4 moles of carbon dioxide (CO₂)

then 1.92 moles of acetylene (C₂H₂) produces X moles of carbon dioxide (CO₂)

X = (1.92 × 4) / 2 = 3.84 moles of carbon dioxide (CO₂)

mass = number of moles × molecular weight

mass of carbon dioxide (CO₂) = 3.84 × 44 = 168.96 g

Learn more about:

combustion of hydrocarbons

brainly.com/question/4919676

brainly.com/question/1406903

#learnwithBrainly

6 0
3 years ago
What is the percent yield of O2 if 10.2 g of O2 is produced from the decomposition of 17.0 g of H2O?
yawa3891 [41]

The balanced chemical reaction will be:

2H2O = 2H2 + O2

<span>We are given the amount of water used in the decomposition reaction. This will be our starting point.</span>

<span>17.0 g H2O</span> (1 mol  H2O/ 18.02 g H2O) (1 mol O2/2 mol <span>H2O</span>) ( 32.00 g O2/1mol O2) = 15.09 g O2

Percent yield = actual yield / theoretical yield x 100

<span>Percent yield =10.2 g / 15.09  g x 100</span>

Percent yield = 67.58%

5 0
3 years ago
Read 2 more answers
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