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professor190 [17]
3 years ago
6

What is 85% of 352???????????????????

Chemistry
1 answer:
slava [35]3 years ago
4 0
85\% \cdot 35 =  \frac{85}{100} \cdot35 =  \frac{2975}{100}=\boxed{29.75}
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Oxidation of methane
Mandarinka [93]

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➪Methane (CH4) is oxidized with molecu- lar oxygen (O2) to carbon dioxide (CO2).

4 0
3 years ago
PLEASE HELP!!
NARA [144]
We can skip option B and D because NaCl is salt and H₂SO₄ is a strong acid.
Neutralization reactions are those reactions in which acid and base react to form salt and water.
As water being amphoteric in nature can react with HCl as follow,

                           HCl  +  H₂O   ⇆  H₃O⁺  +  OH⁻

In this case no salt is formed, so we can skip this option.

Ammonia being a weak base can abstract proton from HCl as follow,

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3 0
2 years ago
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Solution of the Schrödinger wave equation for the hydrogen atom results in a set of functions (orbitals) that describe the behav
kvv77 [185]

Answer :

'n' specifies  → (B) The energy and average distance from the nucleus.

'l' specifies   → (C) The subshell orbital shape.

'ml' specifies → (A) The orbital orientation.

Explanation :

Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as m_l. The value of this quantum number ranges from (-l\text{ to }+l). When l = 2, the value of

Spin Quantum number : It describes the direction of electron spin. This is represented as m_s. The value of this is +\frac{1}{2} for upward spin and -\frac{1}{2} for downward spin.

As per question we conclude that,

'n' specifies  → The energy and average distance from the nucleus.

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'ml' specifies → The orbital orientation.

5 0
3 years ago
Use the molar bond enthalpy data in the table to estimate the value of Δ∘rxn
MakcuM [25]

Answer:

ΔH°rxn = - 433.1 KJ/mol

Explanation:

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∴ ΔH°Cl2(g) = 0 KJ/mol.....pure element in its reference state

∴ ΔH°CCl4(g) = - 138.7 KJ/mol

∴ ΔH°HCl(g) = - 92.3 KJ/mol

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⇒ ΔH°rxn = 4(- 92.3 KJ/mol) + (- 138.7 KJ/mol) - 4(0 KJ/mol) - (- 74.8 KJ/mol)

⇒  ΔH°rxn = - 369.2 KJ/mol - 138.7 KJ/mol - 0 KJ/mol + 74.8 KJ/mol

⇒ ΔH°rxn = - 433.1 KJ/mol

4 0
3 years ago
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Answer:

Properties of metals, worksheet 6.1

Explanation:

Download pdf
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3 years ago
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