The given question is incomplete. The complete question is:
Photosynthesis reactions in green plants use carbon dioxide and water to produce glucose (C6H12O6) and oxygen. A plant has 88.0 g of carbon dioxide and 64.0 g of water available for photosynthesis. Determine the mass of glucose (C6H1206) produced
Answer: 60.0 g of glucose
Explanation:
To calculate the moles, we use the equation:
a) moles of 
b) moles of 
According to stoichiometry :
6 moles of require = 6 moles of
Thus 2.0 moles of require=
of
Thus is the limiting reagent as it limits the formation of product.
As 6 moles of give = 1 moles of glucose
Thus 2.0 moles of give =
of glucose
Mass of glucose = 
Thus 60.0 g of glucose will be produced from 88.0 g of carbon dioxide and 64.0 g of water
Answer:
20cm=the length of the causation that it loads about the contrasting of the solution it is an easy question to answer it just has too many parts I answered one and I hope it helped to give you a hint towards solving the whole thing good luck
Explanation:
I tried!
Answer:
0.10M HCN < 0.10 M HClO < 0.10 M HNO₂ < 0.10 M HNO₃
Explanation:
We are comparing acids with the same concentration. So what we have to do first is to determine if we have any strong acid and for the rest ( weak acids ) compare them by their Ka´s ( look for them in reference tables ) since we know the larger the Ka, the more Hydronium concentration will be in these solutions at the same concentration.
HNO₃ is a strong acid and will have the largest hydronium concentration.
HCN Ka = 6.2 x 10⁻¹⁰
HNO₂ Ka = 4.0 x 10⁻⁴
HClO Ka = 3.0 x 10⁻⁸
The ranking from smallest to largest hydronium concentration will then be:
0.10M HCN < 0.10 M HClO < 0.10 M HNO₂ < 0.10 M HNO₃
Answer:
0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL
Explanation:
The KHP reacts with NaOH as follows:
KHP + NaOH → KNaP + H₂O
<em>Where 1 mole of KHP reacts per mole of KNaP</em>
<em />
That means, the moles of KHP added to the NaOH solution = Moles NaOH at equivalence point. With the moles of NaOH and the volume in liters we can find the molar concentration of NaOH.
<em>Assuming the volume added of KHP was 25.50mL and the solution of NaOH contains 30.0mL (0.0300L), the concentration of the NaOH is:</em>
<em />
<em>Moles KHP = Moles NaOH:</em>
25.50mL = 0.02550L * (0.500mol / L) = 0.01275 moles KHP = Moles NaOH
<em>Molarity NaOH:</em>
0.01275 moles NaOH / 0.0300L =
<h3>0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL</h3>
