Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5
Answer:
6
Step-by-step explanation:
Answer:
Step-by-step explanation:
Properties of a bar graph:
1). There should be equal space between the bars or the columns.
2). Width of each bar or columns should be same.
3). All bars should have same base.
4). Height of each bar will show the value of the data.
By these properties,
- Space between London-Paris, Rome-Oslo are not equal.
- Width of Munich bar is different from other bars.
The answer to A is the pic below
A straight horizontal line where the y-intercept is -3
