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Effectus [21]
2 years ago
12

Question 6

Mathematics
1 answer:
oee [108]2 years ago
7 0

Answer:

The answer is 200km

Step-by-step explanation:

250\5=50,50×4=200

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4 Consider the triangle below.
Maurinko [17]
<h2>=>> <u>Solution (part A</u>) :</h2>

Given :

▪︎Triangle AMG is an isosceles triangle.

▪︎Measure of segment AM = (x+1.4) inches

▪︎Measure of segment MG = (2x+0.1) inches

▪︎Measure of segment AG = (3x-0.4) inches

▪︎segment AG is the base of triangle AMG.

Since AG is the base of the isosceles triangle AMG, segment AM and segment MG will be equal.

Which means :

= \tt x + 1.4 = 2x + 0.1

= \tt x + 1.4 - 0.1 = 2x

=  \tt \: x + 1.3 = 2x

= \tt 1.3 = 2x - x

\color{plum} \hookrightarrow  \tt x = 1.3

Thus, the value of x = 1.3

Therefore :

▪︎The value of x = 1.3

<h2>=>> <u>Solution (Part B)</u> :</h2>

We know that :

▪︎The value of x = 1.3

Which means :

The length of the leg AM :

= \tt x + 1.4

= \tt 1.3 + 1.4

\color{plum} \tt leg \: AM= 2.7 \: inches

Thus, the length of the leg AM = 2.7 inches

The length of leg MG :

= \tt 2x + 0.1

=  \tt2 \times 1.3 + 0.1

= \tt 2.6 + 0.1

\color{plum} \tt\: leg \:MG = 2.7 \: inches

Thus, the length of the leg MG = 2.7 inches

Since the measure of the two legs are equal (2.7=2.7), we can conclude that we have found out the correct length of each leg.

Therefore :

▪︎Measure of leg AM = 2.7 inches

▪︎Measure of leg MG = 2.7 inches

<h2>=>> <u>Solution </u><u>(</u><u>part C</u><u>)</u> :</h2>

We know that :

Value of x = 1.3

Then, measure of the base AG :

=  \tt 3x - 0.4

= \tt 3 \times 1.3 - 0.4

= \tt 3.9 - 0.4

\color{plum}\tt \: Base  \: AG = 3.5 \:  inches

Thus, the measure of the base = 3.5 inches

Therefore :

▪︎ the length of base AG = 3.5 inches.

6 0
2 years ago
Simplify the following by collecting together like terms.<br><br> 3p-4q+9p-6q+1
EleoNora [17]

Answer:

12p-10q+1

it's saying im being rude

3 0
2 years ago
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What is the value of this expression? 42+3×5−(15−3×6)2 4 2 + 3 × 5 − ( 15 − 3 × 6 ) 2
kenny6666 [7]
The solution is the B. 22
6 0
3 years ago
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What's the square root of 628
Galina-37 [17]
4rt33 or 4 times the square root of 33
4 = the square root of sixteen, so the square root of 16 times the square root of 33 = the square root of 628
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26,862÷407= <br> PLZZZZ HELPPP
tino4ka555 [31]
26,862 divided by 407 is 66

Here's the long division way that shows how you get 66

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