3 years ago

WILL MARK BRAINLIEST!!!! BRAINLIEST! Write 206 in base 7

Mathematics

2 answers:

mario62 [17]3 years ago

6 0

Answer:

appreciate it man

Step-by-step explanation:

best of luck

tensa zangetsu [6.8K]3 years ago

5 0

Answer:

104

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago

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gulaghasi [49]

Answer:

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Step-by-step explanation:

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3 years ago

What are the values that satisfy the trigonometric equation for: 0≤q≤2π ? sin(∅)+tan(−∅)

Mrac [35]

Answer:

First choice: 0, pi

Step-by-step explanation:

I am assuming the equation is

$\sin q + \tan (-q) = 0$

(the =0 part is missing in the original problem)

$\sin q + \tan (-q) = 0\\\sin q + \frac{\sin (-q) }{\cos (-q)} = 0\\\sin q + \frac{-\sin q}{\cos q}=0\\\sin q = \frac{\sin q}{\cos q}\\\sin q \cdot \cos q = \sin q\,\,,\,\,\, 0\leq q \leq 2\pi\\\implies\\\cos q = 1 \implies q=\{0, 2\pi\}\\\mbox{or}\\\sin q = 0 \implies q=\{0, \pi, 2\pi\}\\\implies\\q=\{0,\pi,2\pi\}$