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solniwko [45]
3 years ago
15

Choose the best description of the following number 18

Mathematics
1 answer:
Mrac [35]3 years ago
5 0

Answer:

4.243

step by step explanation:

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What’s the approximate value of x?
drek231 [11]

Answer:

Option C: 4

Step-by-step explanation:

<u>Use the Pythagorean Theorem:</u>

a^2+b^2=c^2

3^2+b^2=5^2

9+b^2=25

b^2=16

b=4

Therefore, the value of x is 4.

4 0
2 years ago
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A Pedro le dieron de aguinaldo el triple de lo que recibe de sueldo en un mes. Si pagó una deuda de $4500.00 y aún le quedaron $
Kitty [74]

Answer:

0019273637282.3.5 y .u uowiwotjuirooiqjdjcnncnxndhsiwj nxjsisisiiwhdvdhsjwndbxuakwnsbsuwkwnnshwjwnhidjwjbsusjwvshiw bdhxuiwjsjsbduisishshwqwjbsuijbshiwojsbhdxjsisisiusjjjsjdhdbbdbdbdjejwiwi wuejdjdjjendbdbdbdbdjejeieiejejejjsjsjsjnendjjsksiskoaoakaooiaoajsjjsjwjjwjsisnw vhxjwkaowjnendushwjsisisikwkwkwksbbdhd sjjsisjwjejsjjsisjsnhduisiwjebdvgxyiabwnsnkzisjsvehsguwiwjehhdjsusiwikwkwksjs

8 0
3 years ago
What is the circumference of a circle with a diameter of 50 mm?
Doss [256]
157.1 mm

C x d
3.14 x 50
3 0
3 years ago
Consider the game of independently throwing three fair six-sided dice. There are six combi- nations in which the three resulting
Murrr4er [49]

Answer:

See explanation below.

Step-by-step explanation:

1) First let's take a look at the combinations that sum up 10:

  1. 1+3+ 6,
  2. 1+ 4+ 5,
  3. 2+2+6,
  4. 2+3+5,
  5. 2 + 4 + 4,
  6. 3+3+4

Notice that when we have 3 different numbers on the dice, we can permute them in 6 different ways. For example: Let's take 1 + 3 + 6, we can get this sum with these permutations:

1 + 3 + 6, 1 + 6 + 3, 3 + 6 + 1, 3 + 1 + 6, 6 + 1 + 3, 6 + 3 + 1.

And when we have two different numbers on the dice, we can permute them in 3 different ways:

2 + 2 + 6, 2 + 6 +2, 6 + 2 + 2.

So now we're going to write down the 6 combinations that sum up 10 but we're going to write down how many permutations of them we get:

  1. 1+3+ 6 : 6 permutations
  2. 1+ 4+ 5 : 6 permutations
  3. 2+2+6: 3 permutations
  4. 2+3+5: 6 permutations
  5. 2 + 4 + 4: 3 permutations
  6. 3+3+4: 3 permutations

Total of permutations: 6 + 6 + 3 + 6 + 3 + 3 =27.

Thus we have 27 different ways of getting a sum of 10.

2) Now we're going to take a look at the combinations that sum up 9 and we're going to proceed in a similar way:

  1. 1 + 2 + 6: 6 permutations
  2. 1+3+5: 6 permutations
  3. 1+4+4: 3 permutations
  4. 2+ 3+ 4: 6 permutations
  5. 2+2 +5: 3 permutations
  6. 3+3+3: 1 permutation.

Total of permutations: 6 + 6 + 3 + 6 +3 + 1 = 25.

Thus we have 25 different ways of getting a sum of 10

And we can conclude that the probability of getting a total of 10 is larger than the probability to get a total of 9.

5 0
3 years ago
Which is the graph of x-y=1
labwork [276]

Answer:

here you go! :)

hope it helps!

Step-by-step explanation:

8 0
3 years ago
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