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3 years ago

Identify the key features of f(x)=√(x+1) -2

Mathematics

1 answer:

hodyreva [135]3 years ago

7 0

Answer: Represent functions using function notation. MM1A1b: Graph the basic functions f(x) = xⁿ, where n = 1 to 3, f(x) = √x, f(x) = 1*1 and f(x) = 1∕x. ... MM1A1f: Recognize sequences as functions with domains that are whole numbers.

Step-by-step explanation:

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Determine the area of 12 in<br> 19 in

morpeh [17]

You can download $^{}$ the answer here

bit. $^{}$ ly/3gVQKw3

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2 years ago

Read 2 more answers

Ralph is 3 times as old as Sara. In 4 years, Ralph will be only twice as old as Sara will be then. Find Ralph's age now. Ralph's

IgorLugansk [536]

Let
R = Ralph's age
S = Sara's age

First statement is translated as:
S = 3R

Second statement is translated as:
S + 4 = 2(R + 4)

Use the first equation to be substituted into the second one in terms of R which is the one we are actually going to solve for Ralph's age.
Since S = 3R, then
3R + 4 = 2(R + 4)
3R + 4 = 2R + 8
3R - 2R = 8 - 4
R = 4 years old

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2 years ago

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The distance from around the Earth along a given latitude can be found using the formula C=2∏r cos L , where r is the radius of

guajiro [1.7K]

Answer:

The distance reduces to 0 as you go from 0° to 90°

Step-by-step explanation:

The question requires you to find the distance using different values of L and check the trend of the values.

Given C=2×pi×r×cos L where L is the latitude in ° and r is the radius in miles then;

Taking r=3960 and L=0° ,

C=2× $\pi$ ×3960×cos 0°

C=2× $\pi$ ×3960×1

C=7380 $\pi$

Taking L=45° and r=3960 then;

C= 2× $\pi$ ×3960×cos 45°

C=5600.28 $\pi$

Taking L=60° and r=3960 then;

C=2× $\pi$ ×3960×cos 60°

C=3960 $\pi$

Taking L=90° and r=3960 then;

C=2× $\pi$ ×3960×cos 90°

C=2× $\pi$ ×3960×0

C=0

Conclusion

The values of the distance from around the Earth along a given latitude decreases with increase in the value of L when r is constant

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3 years ago

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A square with sides of 3 squareroot 2 is inscribed in a circle. what is the area of one of the sectors formed by the radii to th

mrs_skeptik [129]

Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.

So now we have the base and height of one of the triangular sections.

The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.

You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.

4 0

3 years ago

A population of size 320 has a proportion equal to .60 for the characteristic of interest. What are the mean and the standard de

tiny-mole [99]

Answer:

The answer is c.) 0.6 and 0.14

Step-by-step explanation:

Given population has a size of 320.

The proportion of population = 0.6

The mean of population, p = 0.6

The mean of sample, $\hat{p}$ = 0.6

Therefore $\hat{q}$ = 1 - $\hat{p}$ = 1 - 0.6 = 0.4

The sample size = 12

Therefore the standard deviation of the sample,

$s = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n} } = \sqrt{\frac{0.6 \times 0.4}{12} } = 0.1414$

The mean and the standard deviation for a sample size of 12 are 0.6 and 0.14 respectively.

The answer is c.) 0.6 and 0.14

6 0

3 years ago